Let a=b
a^2=ab
a^2+a^2=a^2+ab
2a^2=a^2+ab
2a^2-2ab=a^2+ab-2ab
2a^2-2ab=a^2-ab
2(a^2-ab)=1(a^2-ab)
Cancelling (a^2-ab)
Thus;2=1
Improved Answer:-
Let x = y
So x-y = 0
And 2x-2y = 0
Then it follows that 1x-1y = 2x-2y
Therefore 1(x-y) = 2(x-y)
Divide both sides by (x-y)
Thus 1 = 2
The difference of algebra and algebra 1 is that in algebra they teach you the basics. For example, they teach you about variables, graphs, how to find slopes. In algebra 1 they start using equations and and teach you how to work longer equations and all that jazz.
it is a straight line equation with a slope of 1 and a y intercept of -4
1=6x x=1/6
How do you pass Algebra 1? go to class do your work be ontime ask for help
I think there's a typo, otherwise -3 = 1
The difference of algebra and algebra 1 is that in algebra they teach you the basics. For example, they teach you about variables, graphs, how to find slopes. In algebra 1 they start using equations and and teach you how to work longer equations and all that jazz.
I probably ought to work on my Algebra 1 project this weekend.
it is a straight line equation with a slope of 1 and a y intercept of -4
8n = 1 n = 1/8
1=6x x=1/6
How do you pass Algebra 1? go to class do your work be ontime ask for help
1/a = 1/b: cross multiplying gives a = b
I think there's a typo, otherwise -3 = 1
That depends on the value of c. By itself, there's nothing else you can do to that to find out what it equals.
It is missing some information so, is therefore is an incomplete output.
If: 1/2 = q+2/3 Then: q = -1/6
The algebra is used when a component to solve something is missed... Using the algebra you can simply identify or find a lost value. for example: if a worker A does a job in 35 hours, and a worker B does it in 14 hours, how much time they will use to make the work together? Solution: 1/35 + 1/14 = 1/x Minimum multiple= 70x 2x(1) + 5x(1) = 70 (1) 2x + 5x = 70 7x = 70 x = 10 Doing work together, A & B finish a work in 10 hours