Let a=b
a^2=ab
a^2+a^2=a^2+ab
2a^2=a^2+ab
2a^2-2ab=a^2+ab-2ab
2a^2-2ab=a^2-ab
2(a^2-ab)=1(a^2-ab)
Cancelling (a^2-ab)
Thus;2=1
Improved Answer:-
Let x = y
So x-y = 0
And 2x-2y = 0
Then it follows that 1x-1y = 2x-2y
Therefore 1(x-y) = 2(x-y)
Divide both sides by (x-y)
Thus 1 = 2
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It is not possible to show that 1 equals 2 using algebra. Algebra is based on logical rules and principles, and the equation 1 = 2 is not logically valid. It may be possible to construct a false proof or flawed argument that seems to demonstrate 1 equals 2, but this would involve a mathematical mistake or an invalid assumption.
The difference of algebra and algebra 1 is that in algebra they teach you the basics. For example, they teach you about variables, graphs, how to find slopes. In algebra 1 they start using equations and and teach you how to work longer equations and all that jazz.
it is a straight line equation with a slope of 1 and a y intercept of -4
1=6x x=1/6
How do you pass Algebra 1? go to class do your work be ontime ask for help
I think there's a typo, otherwise -3 = 1