If the areas of the three faces are x, y and z then the volume is sqrt(x*y*z).
Proof:
Suppose the sides of the cuboid are a, b and c.
Then the different areas of the faces are ab, bc and ca.
If these are called x, y and z, then x*y*z = ab*bc*ca = (a*b*c)^2
and that, as yuo will notice, is the square of the volume.
Given a cuboid it is always possible to have a cylinder with the same volume.
width = volume/(length*height)
A cuboid fits the description given
By dividing length times width into its given volume
A CUBOID WITH LENGTHS l UNITS, WIDTH w UNITS & HEIGHT h UNITS HAS A VOLUME OF V CUBIC UNITS GIVEN BYV = l*w*h =lwh
It depends on what numbers are squared. The length, width and height MUST be linear measures: they cannot be given in square units. You could have been given the areas of the faces, in which case there is a simple but different method to calculate the volume.
Given a cuboid it is always possible to have a cylinder with the same volume.
width = volume/(length*height)
A cuboid could fit the given description
A cuboid fits the description given
With great difficulty because more information about the dimensions of the cuboid are required.
Volume =Length×Width×Height Substitute the given dimensions: Volume = 5×2×1=10 So, the volume of the cuboid is 10 cubic units.
A cuboid or a cube would fit the given description.
A cuboid, of a given volume, has minimum length etc when each of them is equal to the cube root of the volume.
By dividing length times width into its given volume
A cube or a cuboid would fit the given description of 12 edges and 6 faces.
A CUBOID WITH LENGTHS l UNITS, WIDTH w UNITS & HEIGHT h UNITS HAS A VOLUME OF V CUBIC UNITS GIVEN BYV = l*w*h =lwh