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Answer: v=u + at
v (Velocity) = u (Starting velocity) + a (acceleration) x t (time)
So, starting from stationary (u=0), the velocity is simply a x t
e.g. if the acceleration is 5mph per second per second, after 10 seconds you would be travelling at 50mph.
Answer: The above is for constant acceleration. In the case of variable acceleration, integration has to be used.
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What is the acceleration in science if you know average speed and time?
If you know average speed then you cannot determine the acceleration: the very nature of being a average hides all the increases and decreases in speed which are the accelerations (technically, acceleration is change of speed in a direction). All average speed tells you is the constant speed at which you require to travel to cover the given distance in the given time; as the speed is constant, the acceleration is zero.
Example of derived quantity?
velocity work force acceleration
What is the formula for velocity if you don't know the distance?
You need to know the change in distance between two points in time, not the distances [from a fixed point] themselves. If you know the initial velocity (u) and acceleration (a), then you can work out the velocity (v) after t units of time as v = u + at
How velocity of an object can affect the work done by the object when moving up and inclined?
work = force * distance and force = mass * acceleration and acceleration = change in velosity/change in time so work = mass * acceleration * distance , as a result work = mass * change in velosity/change in time * distance, hence the velocity of the object affected by : 1.mass of the object. 2. gravitational acceleration which reduces the speed of the object when go up and increases the speed of the object when it come down.. 3. look at the rules etc........thx..............with best regards
How can you find velocity from only force and mass?
You would need to use the equation f=ma In this equation, f means force, m means mass, and a means acceleration. So dividing the force by the mass will give you a figure for acceleration. If you know how long the object has been accelerating for, or how far, and what the initial velocity was (or whether it started off still) then you can work out the velocity from this acceleration.
How do you find the initial velocity just with the accelaration final velocity and time?
To find acceleration, you take Vi [Initial Velocity] and you subtract if from Vf [Final Velocity.] (Vi - Vf) If they Vi and Vf are already given, you take the two givens and you subtract them from each other. Vi minus Vf. Do not do Vf minus Vi or it will be wrong. After you do that, you divide your answer from T [Time] (Vi - Vf) a= _____ t Once you get your answer, that will be your acceleration.
What is the acceleration in science if you know average speed and time?
If you know average speed then you cannot determine the acceleration: the very nature of being a average hides all the increases and decreases in speed which are the accelerations (technically, acceleration is change of speed in a direction). All average speed tells you is the constant speed at which you require to travel to cover the given distance in the given time; as the speed is constant, the acceleration is zero.
Does work done in moving a charge from infinity to a given point involves any acceleration?
No, work done in moving a charge from infinity to a given point does not involve any acceleration. Work is defined as the product of force and displacement, and in the case of moving a charge, the force is constant along the path. Since acceleration is the rate of change of velocity, and there is no change in velocity in this case, there is no acceleration involved.
How do you find acceleration from speed?
If speed does not change, then acceleration is 0 To find acceleration, you must also know the time Speed = metres per second. Acceleration = meters per second, per second Therefore you can use the equation m/s2 to find the acceleration. change in speed/ change in time.
Is accelleration the rate at which work is accomplished?
No, acceleration is change in velocity over time. Power is the rate at which work is being accomplished.
How do you work out a distance math problem?
This all depends on the problem given. The basic forms to work out the "compatible" quantity(ies) for the distance math problem are:distance = velocity x timevelocity = acceleration x timeIn some higher level courses, you will learn these courses:h(t) = h0 + v0t - ½gt² [The height of the projectile, given the gravity g]v(t) = v0 + at [The general velocity formula]v(t) = √(v0² + 2ad) [The velocity formula, given the distance and acceleration and the initial velocity]
How do you work out velocity acceleration?
v2 = v02 + 2a(delta x)v = sqrt(v02 + 2a(delta x))This is based on the assumption that there is constant acceleration.Another way to find velocity is using a little Calculus, this method is better since it does not assume constant acceleration, therefore this would work even if there is a change in acceleration.Since v = dx/dt, you can differentiate position with respects to time to find instantaneous velocity, given that you do know the time.And dv/dt = a, therefore dv = a x dt, integrate both sides you get velocity. This approach again requires the knowledge of time.
How do you find work when given force velocity and time?
Work W=Pt power times time, W = FVt.
Give examples of derived quantities?
work,velocity,force and acceleration
Example of derived quantity?
velocity work force acceleration
How does acceleration occur?
acceleration work by speed when something is going fast and when it and go over or faster with something.
How calculate distance if you are given velocity and deceleration?
First you must know the initial velocity, the acceleration, and the time it takes to reach 0 velocity. Use this equation: d=Vi+(at²)/2, where Vi is initial velocity, a is acceleration, and t is time. Here is an example, let's say Vi=25 m/s Vf=0 a=-10m/s/s t=1.7s d=25+[-10(1.7²)/2] -> 1.7² = 2.89 -> -10(2.89)=-28.9 -> -28.9/2=-14.45 d=25+(-14.45) d=10.55 Therefore, the object traveled 10.55m before stopping. Also, sorry for not including units in the example; it would have been messy :P And the -> between parts in the equation is me trying to make arrows to separate my work, in case that confused you.
