Since the question doesn't say that it should only be those digits, the answer could be 100.000, or even with roman numerals LXXXXX, though neither is really written in a normal manner.
More commonly, basic math operations (addition, subtraction, multiplication, and division) would be used in combination to reach 100:
111-11
33*3+3/3
5*5*5-(5*5)
are some examples.
A prime number with identical digits is 11.
5*5*5 - 5*5 = 100
The number 11 is prime and has two identical digits.
11 is the only prime number with identical digits. After 11 all numbers with identical digits can be divided by atleast 11 or 3.
Oh, dude, consecutive identical digits are just fancy words for when you have the same number back-to-back. Like when you see 22 or 777 in a row. It's not rocket science, just a fun little pattern that shows up in numbers.
1/1
Like so: 100,000,000
The 2-digit multiples of 11 all have identical digits.
One over one
There is none. Any number formed from 3 identical digits must have a digital root of 0, 3 or 6. These are, therefore, the only possible remainders when divided by 9. Note: The digital root of a number is the sum of all its digits. If the answer is greater than 9, repeat the process.
"5d in a z c" means 5 Digits in aZip Code.
1/1 = 1