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Q: How can you get 441 by using 4 prime numbers?

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2 + 3 + 5 + 431 = 441

3 x 3 x 7 x 7 = 441

3 x 3 x 7 x 7

To find the prime factors of a number, you should start by dividing it by any obvious divisors. In this case, the digit sum of 441 is 9, and so we know that it can divide by 9. Do this and we get 49, which is known from times tables to be 7x7. 9 can be broken down into 3x3. Thus the number 441 can be expressed as 3x3x7x7.

1764

It is: 2*5^4 = 1250

2, 3, 5, And 7 are the first 4 prime numbers

441 can be written as 4.41 × 102 or expanded as (4 x 102) + (4 x 101) + (1 x 100)

441

4 is not prime.

The question is quite ambiguous. If you're talking about all the even prime numbers between 4 and 50, then the sum is zero. No even number, except '2', is a prime number, so there aren't any between 4 and 50..

No they are not prime numbers because 4 is composite.

The prime numbers from 1 to 4 are 2 and 3.

No. If they end in 4, they are even numbers and divisible by 2, and therefore are not prime.

There are no even prime numbers in that range.

It's neither of them because -4 is not a natural number and prime or composite numbers are a subset of natural numbers i.e. only natural numbers can be classified as prime or composite numbers.

The numbers are CO-prime, but not necessarily prime numbers: think of 3 and 4....

Prime numbers : 2, 3, 5, 7 Composite numbers : 4, 6, 8, 9

There aren't any prime numbers divisible by 4. Prime numbers aren't divisible by anything except 1 and the number.

4 88?

You might be thinking of relatively prime numbers. Two numbers are considered relatively prime if their GCF is 1. 4 and 9 are relatively prime.

47 does not have 4 prime numbers (factors or divisors).

2 is the only prime factor of 4.

4 and 25 are not prime numbers.

Example: 4 and 9 2 x 2 = 4 3 x 3 = 9 No common prime factors. The GCF is 1. The numbers are relatively prime.