0
You have to use the manipulator oct:
#include
#include
using std::cin;
using std::cout;
using std::endl;
using std::oct;
int main()
{
int num = 0;
cout << endl << "Enter a number to convert to octal: ";
cin >> num;
cout << endl << "Number " << num << " in octal "
<< oct << showbase << num
<< endl;
system("PAUSE");
return 0;
}
What else can I help you with?
Write a Java program to get the ASCII value of the given number?
If you look up the ASCII values for digits, you'll see that 0 = 48, 1 = 49... 9 = 57. So it's a simple matter of adding 48 to your digit to find out the ASCII value for it.
Write a C program to accept a string from user and display its ascii value and then display sum of all ascii value of strings?
//C program to accept a string from user and //display its ascii value and //then display sum of all ascii value of strings #include<stdio.h> #include <string.h> int main() { char String[100]; int Sum,Index; Sum=0; //Sum is initially zero printf("Enter the string:\n"); gets(String); //Accept String from User for(Index=0;Index<strlen(String);Index++) { Sum+=(String[Index]); //Adds (the ASCII values of) the String characters. } printf("The sum is %d\n",Sum); //Printing it as %d gives the equivalent ASCII value. return 0; }
How do you write a C program to convert a binary value to its octal equivalent?
To convert from binary to octal, bitwise AND the binary value with 0x8 (00000111 in binary) and push the value onto a stack. Right-shift (>>) the binary value by 3 bits and repeat until the binary value is zero. Pop the stack to build the left-to-right digits of the octal value. Using 10110100 as an example: 10110100 & 00000111 = 00000100 10110100 >> 3 = 00010110 00010110 & 00000111 = 00000110 00010110 >> 3 = 00000010 00000010 & 00000111 = 00000010 00000010 >> 3 = 00000000 Popping the values in order reveals 00000010, 00000110 and 00000100 (decimal 2, 6 and 4 respectively). Thus 10110100 binary is 0264 octal.
Why not is there an exact value of pie?
There is an exact value - we just can't write it in numbers.
Write a program that prints a table of the binary octal and hexadecimal equivalents of the decimal numbers in the range 1 through to 256?
import java.util.Scanner; public class NumberSystem { public void displayConversion() { Scanner input = new Scanner(System.in); System.out.printf("%-20s%-20s%-20s%-20s\n", "Decimal", "Binary", "Octal", "Hexadecimal"); for ( int i = 1; i <= 256; i++ ) { String binary = Integer.toBinaryString(i); String octal = Integer.toOctalString(i); String hexadecimal = Integer.toHexString(i); System.out.format("%-20d%-20s%-20s%-20s\n", i, binary, octal, hexadecimal); } } // returns a string representation of the decimal number in binary public String toBinaryString( int dec ) { String binary = " "; while (dec >= 1 ) { int value = dec % 2; binary = value + binary; dec /= 2; } return binary; } //returns a string representation of the number in octal public String toOctalString( int dec ) { String octal = " "; while ( dec >= 1 ) { int value = dec % 8; octal = value + octal; dec /= 8; } return octal; } public String toHexString( int dec ) { String hexadecimal = " "; while ( dec >= 1 ) { int value = dec % 16; switch (value) { case 10: hexadecimal = "A" + hexadecimal; break; case 11: hexadecimal = "B" + hexadecimal; break; case 12: hexadecimal = "C" + hexadecimal; break; case 13: hexadecimal = "D" + hexadecimal; break; case 14: hexadecimal = "E" + hexadecimal; break; case 15: hexadecimal = "F" + hexadecimal; break; default: hexadecimal = value + hexadecimal; break; } dec /= 16; } return hexadecimal; } public static void main( String args[]) { NumberSystem apps = new NumberSystem(); apps.displayConversion(); } }
Why are these octal codes used instead of decimal system?
Octal codes are often used to write the numerical value of a binary number because it is easier to convert from binary to octal, instead of binary to decimal. You can convert to octal on sight, and it simply requires grouping the binary bits into groups of three, whereas converting to decimal requires repeated division by 10102 or 1010. Actually, grouping into three bits is the same as dividing by 1002 or 810 so the process is really the same. Divide by 8 to get octal. Divide by 10 to get decimal.
How do you write the number 25 in octal?
To write the number 25 in octal, you need to convert it from decimal to octal. You can do this by dividing the number by 8 and recording the remainders. Dividing 25 by 8 gives a quotient of 3 and a remainder of 1. Then taking the quotient (3), dividing it by 8 gives a quotient of 0 and a remainder of 3. Reading the remainders from last to first, 25 in octal is written as 31.
Write a program that prints a table of the binary, octal and hexadecimal equivalents of the decimal numbers in the range 1 through 256?
import java.util.Scanner; public class NumberSystem { public void displayConversion() { Scanner input = new Scanner(System.in); System.out.printf("%-20s%-20s%-20s%-20s\n", "Decimal", "Binary", "Octal", "Hexadecimal"); for ( int i = 1; i <= 256; i++ ) { String binary = Integer.toBinaryString(i); String octal = Integer.toOctalString(i); String hexadecimal = Integer.toHexString(i); System.out.format("%-20d%-20s%-20s%-20s\n", i, binary, octal, hexadecimal); } } // returns a string representation of the decimal number in binary public String toBinaryString( int dec ) { String binary = " "; while (dec >= 1 ) { int value = dec % 2; binary = value + binary; dec /= 2; } return binary; } //returns a string representation of the number in octal public String toOctalString( int dec ) { String octal = " "; while ( dec >= 1 ) { int value = dec % 8; octal = value + octal; dec /= 8; } return octal; } public String toHexString( int dec ) { String hexadecimal = " "; while ( dec >= 1 ) { int value = dec % 16; switch (value) { case 10: hexadecimal = "A" + hexadecimal; break; case 11: hexadecimal = "B" + hexadecimal; break; case 12: hexadecimal = "C" + hexadecimal; break; case 13: hexadecimal = "D" + hexadecimal; break; case 14: hexadecimal = "E" + hexadecimal; break; case 15: hexadecimal = "F" + hexadecimal; break; default: hexadecimal = value + hexadecimal; break; } dec /= 16; } return hexadecimal; } public static void main( String args[]) { NumberSystem apps = new NumberSystem(); apps.displayConversion(); } }
When do children write numbers in words?
To practice place value and spelling.
Using numbers, how do you write 5,200,000?
What is the place value of the 1 in 1,234,567.890?
What is the base 5 value of the number 46?
The value doesn't change. In base-5, you'd have to write it as '141', but you, the decimal guy, the binary guy, and the octal guy would each still have the same number of beans in your respective pockets.
Write A-Z in ASCII code?
A = 0x41 = 65 B = 0x42 = 66 C = 0x43 = 67 ... Y = 0x59 = 89 Z = 0x5A = 90 However, note that depending on a particular numeric or bit value for a character is not always portable. It depends on the implementation.
