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Q: How do you write an equation in slope intercept form when given y intercept and x intercept?

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y intercept is b and slope is m Equation is y = mx + b For example if y intercept (where x = 0) is -3 and slope is 4 then y = 4x-3

y = -x + 8

You don't, because it is undefined.

The equation is y=3x-6 The y intercept is (0,-6) since the equation is already in y=mx+b i.e. slope intercept form where b is the y intercept. The x intercept is found by letting y =0 So we solve 0=3x-6 and 3x=6 or x=2 The x intercept is (2,0)

Slope-Intercept form is the form y=mx+b. Sketching the graph involves plotting the line on the coordinate plane. The easiest way to do that is to create two different points from the equation, plot them on the graph and trace a line through them with a ruler. Showing your steps means showing how you got the equation. Make sure that any math you do in your head you put on the paper. Other than that I don't know how to answer this. Was there supposed to be an actual equation with it?

Related questions

Y=mc+b

y = mx + b, where m is the slope and b is the y-intercept.

Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).

As for example if the slope is 3 and the y intercept is 6 then the equation is: y=3x+6

An equation in slope intercept form is given by y = mx + b, where m is the slope and b is the y-intercept.Examples:If the slope is 3 and the y- intercept is 4, the equation will be, y = 3x + 4If the slope is -1/5 and y-intercept is -2/3, the equation will be, y = -1/2)x - 2/3

-7

y= slope + y-intercept

4

y = 3x/4 + 7

Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4

-12

Slope Intercept form is meant for a line, so if you know the slope m in the equation y=mx+b then with a given point say (3,4) and say the slope of the line was 2 then the equation would read y=2x+4.

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