5+9(n)
To write pseudocode that accepts five numbers and displays their sum and average, you can follow these steps: Initialize a variable sum to 0. Loop five times to accept input for each number, adding each to sum. After the loop, calculate the average by dividing sum by 5. Display both the sum and the average. Here’s a simple representation: BEGIN sum = 0 FOR i FROM 1 TO 5 DO INPUT number sum = sum + number END FOR average = sum / 5 OUTPUT "Sum: ", sum OUTPUT "Average: ", average END
5*(3+x)=15+5x Fifteen plus five times that number
The sum of number and four times a number is 25 write in algebraic expression
Five
7x4+8
5 (9+x) Where x is the "a number"
five times the sum of a number and 8 is -15.
To write pseudocode that accepts five numbers and displays their sum and average, you can follow these steps: Initialize a variable sum to 0. Loop five times to accept input for each number, adding each to sum. After the loop, calculate the average by dividing sum by 5. Display both the sum and the average. Here’s a simple representation: BEGIN sum = 0 FOR i FROM 1 TO 5 DO INPUT number sum = sum + number END FOR average = sum / 5 OUTPUT "Sum: ", sum OUTPUT "Average: ", average END
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
3x+5x
5*(3+x)=15+5x Fifteen plus five times that number
The question is ambiguous and the two possible answers are: Twelve times (a number and 5 times the number) = 12*(n + 5n) = 12*6n = 72n Twelve times a number amd five times the number = 12*n + 5*n = 17*n
The sum of number and four times a number is 25 write in algebraic expression
Five
16x(1+a)
7x4+8
90