To write pseudocode that accepts five numbers and displays their sum and average, you can follow these steps:
sum
to 0.sum
.sum
by 5.sum
and the average
.Here’s a simple representation:
BEGIN
sum = 0
FOR i FROM 1 TO 5 DO
INPUT number
sum = sum + number
END FOR
average = sum / 5
OUTPUT "Sum: ", sum
OUTPUT "Average: ", average
END
1.Start Algorithm 2.Enter first number 3.Enter second number 4.Enter third number 5.Enter fourth number 6.Enter fifth number 7.Add five number 8.display five number / 2 9.Display result 10.End Algorithm
#include <iostream>02using namespace std; 03 04int main() 05{ 06 int sum = 0; 07 int average = 0; 08 int array[10] = {1,2,3,4,5,6,7,8,9,10}; 09 for (int i = 0; i < 10; ++i) 10 sum+=array[i]; 11 average = sum/10; 12 cout<<"Average:"<<average; 13}
Certainly! Here's a simple pseudocode snippet that reads two numbers, multiplies them together, and prints out their product: 1. Read firstNumber 2. Read secondNumber 3. product = firstNumber * secondNumber 4. Print product In this pseudocode, we first read the two numbers, then multiply them to calculate the product, and finally print out the result.
Currency style format
The average of the remaining numbers is 38.
Simply: design an application, that accept one number, then put it in a loop that repeat is ten times.
Develop an algorithm to display all prime numbers from 2 to 100. Give both the pseudocode version and the flowchart version. Convert your pseudocode into a Java program.
1. Accept the 2 numbers 2. Add the 2 numbers3. Compare answer with 54. If answer is greater than 5 subtract with 5 else give a error message.
1.Start Algorithm 2.Enter first number 3.Enter second number 4.Enter third number 5.Enter fourth number 6.Enter fifth number 7.Add five number 8.display five number / 2 9.Display result 10.End Algorithm
No. The MIN function displays the lowest value in a range. The AVERAGE function gets the arithmetic mean of a set of values. It totals them up and divides by the amount of numbers.
How to write a program for mouse in microprocessor?
Algorithm:Given x and y are both numbers, if x is greater than y then return x, otherwise return y.C++ implementation of the algorithm:template T GetMax(T x, T y) { return(x>y?x:y); }
floating-point variable cost
start read a read b c=a-b print c end
Yes. Excel can display numbers as percentages. Do you have a question?
#include <iostream>02using namespace std; 03 04int main() 05{ 06 int sum = 0; 07 int average = 0; 08 int array[10] = {1,2,3,4,5,6,7,8,9,10}; 09 for (int i = 0; i < 10; ++i) 10 sum+=array[i]; 11 average = sum/10; 12 cout<<"Average:"<<average; 13}
Certainly! Here's a simple pseudocode snippet that reads two numbers, multiplies them together, and prints out their product: 1. Read firstNumber 2. Read secondNumber 3. product = firstNumber * secondNumber 4. Print product In this pseudocode, we first read the two numbers, then multiply them to calculate the product, and finally print out the result.