To write pseudocode that accepts five numbers and displays their sum and average, you can follow these steps:
sum
to 0.sum
.sum
by 5.sum
and the average
.Here’s a simple representation:
BEGIN
sum = 0
FOR i FROM 1 TO 5 DO
INPUT number
sum = sum + number
END FOR
average = sum / 5
OUTPUT "Sum: ", sum
OUTPUT "Average: ", average
END
1.Start Algorithm 2.Enter first number 3.Enter second number 4.Enter third number 5.Enter fourth number 6.Enter fifth number 7.Add five number 8.display five number / 2 9.Display result 10.End Algorithm
In pseudocode, you can declare a variable holding real numbers by specifying the variable name followed by its type. For example, you might write REAL numberVariable; or DECLARE numberVariable AS REAL;. This indicates that numberVariable will store a real number value. You can then assign a value to it using an assignment statement, such as numberVariable = 3.14;.
#include <iostream>02using namespace std; 03 04int main() 05{ 06 int sum = 0; 07 int average = 0; 08 int array[10] = {1,2,3,4,5,6,7,8,9,10}; 09 for (int i = 0; i < 10; ++i) 10 sum+=array[i]; 11 average = sum/10; 12 cout<<"Average:"<<average; 13}
Certainly! Here's a simple pseudocode snippet that reads two numbers, multiplies them together, and prints out their product: 1. Read firstNumber 2. Read secondNumber 3. product = firstNumber * secondNumber 4. Print product In this pseudocode, we first read the two numbers, then multiply them to calculate the product, and finally print out the result.
Currency style format
Simply: design an application, that accept one number, then put it in a loop that repeat is ten times.
Develop an algorithm to display all prime numbers from 2 to 100. Give both the pseudocode version and the flowchart version. Convert your pseudocode into a Java program.
1. Accept the 2 numbers 2. Add the 2 numbers3. Compare answer with 54. If answer is greater than 5 subtract with 5 else give a error message.
1.Start Algorithm 2.Enter first number 3.Enter second number 4.Enter third number 5.Enter fourth number 6.Enter fifth number 7.Add five number 8.display five number / 2 9.Display result 10.End Algorithm
No. The MIN function displays the lowest value in a range. The AVERAGE function gets the arithmetic mean of a set of values. It totals them up and divides by the amount of numbers.
How to write a program for mouse in microprocessor?
Algorithm:Given x and y are both numbers, if x is greater than y then return x, otherwise return y.C++ implementation of the algorithm:template T GetMax(T x, T y) { return(x>y?x:y); }
floating-point variable cost
start read a read b c=a-b print c end
Yes. Excel can display numbers as percentages. Do you have a question?
#include <iostream>02using namespace std; 03 04int main() 05{ 06 int sum = 0; 07 int average = 0; 08 int array[10] = {1,2,3,4,5,6,7,8,9,10}; 09 for (int i = 0; i < 10; ++i) 10 sum+=array[i]; 11 average = sum/10; 12 cout<<"Average:"<<average; 13}
Certainly! Here's a simple pseudocode snippet that reads two numbers, multiplies them together, and prints out their product: 1. Read firstNumber 2. Read secondNumber 3. product = firstNumber * secondNumber 4. Print product In this pseudocode, we first read the two numbers, then multiply them to calculate the product, and finally print out the result.