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How do you write length is 4 times the width plus 4 as a formula?
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What is the proper way to write out lxw?
Length times Width (L x W) is a simple equation for area calculation.
What is the answer to A rectangle with an area of 24 in.2 has a length of 8 inches and a width of 3 inches. What is the correct way to write the ratio of its width to length?
It's width to length ratio is 3 : 8.
When the perimiter of the rectangle is 38 inches If the rectangle is less than 4 times the width find the area of the rectangle Confused how to do this?
I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.
How do you find the area of rectangle using function?
The area is the length times the width. That's the function. If you want to write a function in a computer language, you need two parameters. Just return the product of the two parameters. Example in Java: double rectangle_area(double length, double width) { return length * width; } I didn't test this, but that's the basic idea.
How do you write measurements for a box?
The measurements for a box is written thus: length, width and depth.
Write the math formula to determine volume?
Length X Width X Height
What do you write when your doing volume?
If you are dealing with the functions of a square or a rectangle, you write the answer, which is the formula. Length multiplied by the width equals the volume.
Do you write Length x width or width x length?
It doesn't really matter, but most people usually write length x width.
What is the proper way to write out lxw?
Length times Width (L x W) is a simple equation for area calculation.
What is the answer to A rectangle with an area of 24 in.2 has a length of 8 inches and a width of 3 inches. What is the correct way to write the ratio of its width to length?
It's width to length ratio is 3 : 8.
The width of a rectangle is 61 cm and its length is 71 cm Write the ratio of its width to its length as a fraction?
61:71 1:71/61
When the perimiter of the rectangle is 38 inches If the rectangle is less than 4 times the width find the area of the rectangle Confused how to do this?
I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.
How do you find the area of rectangle using function?
The area is the length times the width. That's the function. If you want to write a function in a computer language, you need two parameters. Just return the product of the two parameters. Example in Java: double rectangle_area(double length, double width) { return length * width; } I didn't test this, but that's the basic idea.
How do you write measurements for a box?
The measurements for a box is written thus: length, width and depth.
How do you write an algebraic expression for the area of a rectangle with length meters and width 8 meters?
Having the length x meters and width 8 meters, then the area is 8x square meters.
The length of a rectangle is 3 inches greater than the width Write a polynomial that represents the area of the rectangle?
let x be the width let x+3 be the length The area of a rectangle is length X width Area=(x)(x+3) =x^2+3x
A rectangle field that is 119 square yards in area is to covered by sod. it is known that the field is 3 yards longer than twice the width. find the dimensions of the field. how do i do this?
It is given that the length is twice the width plus 3 yards; this can be written as a formula: Length = 2 × Width + 3 To calculate the area of a rectangle the formula is: Area_rectangle = Length × Width Substitute for Length in the above formula by the given expression involving Width → Area = Length × Width = (2 × Width + 3) × Width = 2 × Width² + 3 × Width But the area is given as 119 sq yd. If I now write w for Width, this gives: 2w² + 3w = 119 sq yd → 2w² +3w - 119 = 0 Which is a quadratic which can be solved either by using the formula or by factorising: It does factorise: the factor pairs of 119 are 1 × 119 and 7 × 17. One bracket will have (2w ...) and the other will have (w...). As the 119 is negative, there are effectively four pairs of numbers that could be fitted into the brackets: {-1, 119}; {-7, 17}; {7, -17}; {1, 119}. There is one pair which will fit so that when multiplied out gives the quadratic. A quadratic will always have two solutions; as one of the numbers above is negative and one positive, the two solutions will comprise of one positive and one negative value for w (Width); as a length must be positive, the negative solution cannot work and the positive solution is the required Width, from which the Length can be calculated (as above).
