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It doesn't really matter, but most people usually write length x width.
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∙ 13y ago
Anonymous
W x L
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What is the formula to find the surface area of a rectangle?
Length X Width.
What is the rule for the perimeter of a rectangle?
The perimeter of a rectangle is found by the following formula: (Length x 2) + (Width x 2) or Length + Length + Width + Width.
Is it height x width x length?
It is a simple equation. It's length x width x height. That is a proper formula for volume.
How do you write an algebraic expression for the area of a rectangle with length meters and width 8 meters?
Having the length x meters and width 8 meters, then the area is 8x square meters.
How do you get the area if you have the width and the perimeter?
Perimeter = 2 lengths + 2 widths 1/2 perimeter = length + width Length = 1/2 perimeter - width Area = length x width That's (1/2 perimeter - width) x (width) .
How do you you get the length if you have the area and the width?
Area = length x width Length = area/width
How do you find width when volume height and length are given?
You really should know how to answer that question.Volume = (length) x (width) x (height) .Length = (volume) / (width x height)Width = (volume) / (length x height)Height = (volume) / (length x width)
How do you find the area and perimeter of a rectangle?
Perimeter: Add the length of the four sides. Area: Multiply length x width.
The length of a rectangle is 3 inches greater than the width Write a polynomial that represents the area of the rectangle?
let x be the width let x+3 be the length The area of a rectangle is length X width Area=(x)(x+3) =x^2+3x
How do you find the height of a rectangular prism when given the length width and volume?
Volume = (length) x (width) x (height)Divide each side of this formula by (length) x (width).Then you have:Height = Volume/(length x width)
Does the formula for volume is length x width?
Volume = Length x Width x Depth
Write the math formula to determine volume?
Length X Width X Height
What is the surface area of the roman Colosseum?
The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.
What is the volume of a rectangle prism?
length x width x height or length x breadth x height
How do you find the perimeter of a rectangle with only the width or length and the area given?
It not possible you nit witt that is not true length x width = area If you know length and area, solve width width = area / length then 2 x length + 2 x width = perimeter
How do you find the height of a box given the width depth and surface area?
divide surface area by width Sorry It is a little more complicated than that. Surface area = (2 X length X width) + (2 X length X height) + (2 X width X height) Solve for height Surface area - (2 X length X width) = 2height(length + width) (Surface area - (2 X length X width))/2(length + width) = height
What Sides of a rectangle give perimeter equal to to area?
perimeter = 2 x (width + length) area = width x length If area = perimeter then: width x length = 2 x width + 2 x length width x length - 2 x length = 2 x width length x (width - 2) = 2 x width length = 2 x width / (width - 2) So any rectangle with length and width that satifies the above will work, for example: width = 2.5, length = 10, area: 2.5 x 10 = 25; perimeter: 2x(2.5+10) = 2x12.5 = 25 width = 3, length = 6, area: 3x6 = 18; perimeter: 2x(3+6) = 2x9 = 18 width = 4, length = 4, area: 4x4 = 16; perimeter: 2x(4+4) = 2x8 = 16 By making the length dependent on the width, the width must be at least 2. Once the 4x4 square has been reached, the width becomes larger than the length, but the pair will also be given if the width is the smaller dimension, for example, a width of 6 gives a length of 2 x 6 / (6 - 2) = 12 / 4 = 3, which matches the length of 6 being given by a width of 3.
