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How do you write square root of 7 plus i in the form of a plus ib?
AmanKumarSoni
It already is in the form a+ib. a = root 7, the b=1 (i.e 1 x i ).
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∙ 12y ago
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What is the square root of 126 plus the square root of 56?
in decimal form the answer is 18.7082869
Square root of 27 plus the square root of 75 equal?
square root of 27 plus the square root of 75
What is the square root of 36 in simplest form?
plus or minus 6
Is the square root of 2 written in surd form?
That is the only way to write it exactly.
Write a c plus plus program to find the square root of a number?
#include<iostream> int main() { unsigned num = 25; // or use user-input to assign the value unsigned root = sqrt ((double) num) std::cout << "The square root of " << num << " is " << root; }
What is the square root of 126 plus the square root of 56?
in decimal form the answer is 18.7082869
What is the square root of 2 plus the square root of 2 in square root form?
The square root of 2 plus the square root of 2 is equal to twice the square root of 2, therefore the correct answer is: 2(√2) or √8
What is four square root of five plus four square root of five in radical form?
45+45+90
How do you factor -9x squared plus 512?
In one bracket, write 16 times the square root of 2 minus 3x. In the other one, write 16 times the square root of 2 plus 3x.
What does the square root of 27 plus the square root of 5?
The square root of 27 plus the square root of 5 = 7.4322204
Square root of 27 plus the square root of 75 equal?
square root of 27 plus the square root of 75
What is the square root of 36 in simplest form?
plus or minus 6
How do you write the square root of K in exponential form?
K0.5
Is the square root of 2 written in surd form?
That is the only way to write it exactly.
Square root of 4x plus the square root of x?
square root of 4x is 2 times square root of x, so answer is square root of x times 3 since it is 2 square roots of x plus one of them
Which two square roots added together equal 11?
The square root of 25 plus the square root of 36 = 11
Write a c plus plus program to find the square root of a number?
#include<iostream> int main() { unsigned num = 25; // or use user-input to assign the value unsigned root = sqrt ((double) num) std::cout << "The square root of " << num << " is " << root; }
