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It is: y = -2x + 1

Let's use the given slope of -2 and the x- and y-coordinates of the given point, (1, -1) to write the slope-intercept form of the equation of the line.

y = mx + b replace -2 for m, -1 for y, and 1 for x

-1 = -2(1) + b

-1 = -2 + b add 2 to both sides

1 = b

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Q: How do you write the equation of the line with a slope of negative 2 and passing through one negative one?
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