The sum of b and 8 would be written b+8 or 8+b(commutative property of addition)
int mul (int a, int b) { int sum= 0; for (; b>0; --b) sum -= -a; for (; b<0; ++b) sum -= a; return sum; }
m + 8
You remember that 'sum' means addition so that's b+11
(3 + -8) - 8
(a+b)/6
It is the same as: 3*(a+b) or simply 3(a+b)
Watch closely:The sum of 'n' and '8' is written as (n + 8).
t +8 = b
The pair of no. Are 8 & 3 Sum is 8+3=11 Product is =8×3= 24
4x - 3 = 8
3(b5)
Given:a + b = 2a - b = 8Then:a = b + 8∴ (b + 8) + b = 2∴ 2b = -6∴ b = -3∴ a = 5