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Q: How do you write the sum of b and 8?

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m + 8

int mul (int a, int b) { int sum= 0; for (; b>0; --b) sum -= -a; for (; b<0; ++b) sum -= a; return sum; }

You remember that 'sum' means addition so that's b+11

(3 + -8) - 8

(a+b)/6

It is the same as: 3*(a+b) or simply 3(a+b)

Watch closely:The sum of 'n' and '8' is written as (n + 8).

Cls input "enter two no.s ",a,b sum=a+b print "sum = ";sum end

#include<stdio.h> main() { int a,b,sum; print f("enter two numbers"); scan f("%d%d",&a&b); sum=a+b print f(the sum of a and b is %d,sum); }

t +8 = b

4x - 3 = 8

You add numbers as follows: sum = a + b;

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