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Q: How do you factor 2b squared plus 9b minus 35?

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(a - 2b)(2a - b)

3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)

There are no like terms here.

This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a

It is: 2b squared

(a + 2b)(a + 2b)

-8

2b - 1

2a

5b + 11 - 2b = 3b + 11

20a plus 14 will be 34a minus 8a minus 7 34a minus 8 is 26a minus 7 is 19a. The single b is 1b plus 6b which is 7b minus 2b equals 5b.

2b

7a-2b

3a - 2b

-2bk2 + 6bk - 2b = -2b(k2 - 3k + 1)

It is an algabraic expession without knowing whether or not 2b and 3a are plus or minus

5a(a+2b+b²)

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals". There is no visible symbol between " ... equals 4" and "2b plus 1".

(a + 2b)(c + 2d)

That will depend on the plus or minus value of 10 or maybe there is a missing equality sign.

4(a + 2b - 4c)

The Answer to this question is 9 (2B+4) and (1B+3)

3a(b+c)+2b(b+c)

b2 x 2b = 2b3

(a - 2b)(c - 3d)