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How do you find the quotient of two numbers when both are positive?
A quotient is the answer to a multiplication problem. Therefore, just multiply the two numbers.
How can you use subtraction to complete an addition problem?
Treat the "plus positive X" as "minus negative X". Example: Positive two plus positive two equals positive four. Positive two minus negative two equals positive four.
Why you are taking only positive values in the logarithms?
You must be referring to some problem where all the numbers are 1 or above.
How many more integers are there than natural numbers?
Actually, natural numbers are your counting numbers such as 1,2,3 etc. Integers include negative AND positive whole numbers. Such as: -99,56m,-895241544,etc. The answer to this problem can be infinite.
Can you subtract positive numbers and get a negative number?
yes, just look at this problem, 3-4=-1. its simple math
What is the math problem for the greatest common factor of 30 48?
The problem is to find the largest positive integer which goes evenly into the two given numbers.
Greater than zero plus?
this question is not complete greater than zero? you need a problem to go with this question
What are the numbers in a diveson problem called?
it depends if you want the answer or the numbers in the problem
Your blood type is A positive and your husband RH positive Can you have a baby with no problems?
positive and positive is not a problem
My blood group is O negative and my wife's B positive any problem for her pregnancy or for kids?
If mother is Rh positive there will be no problem. Problem can arise when mother is negative and baby positive.
Do you change anything to a problem if it is a negative and a positive?
It truly depends on what the problem is, but normally a negative will change the overall answer of the sum: + and - = negative answer - and - = positive answer + and + = positive answer - and + = negative answer
C program to find all possible way that a number can be written as the sum of two or more positive numbers?
It is not that easy, but very interesting problem.
