Pretend both the numbers are positive, find the quotient as normal and then make it negative.
The answer is the normal quotient except negative. Pos X neg = neg
You need two numbers to find a quotient.
Just ignore the signs, and go ahead and multiply or divide your numbers.Then, when you finish multiplying or dividing . . .-- If the two original numbers had the same sign, then the answer is positive.-- If the two original numbers had different signs, then the answer is negative.Easy, eh ?
Find the product of their absolute values (without regard for their signs) and then label the product positive. The process is exactly the same if both numbers are negative.
If the divisor and the dividend are positive then the quotient will be positive too.
Pretend both the numbers are positive, find the quotient as normal and then make it negative.
It is a positive.
The answer is the normal quotient except negative. Pos X neg = neg
You need two numbers to find a quotient.
The sign of a quotient is when you are multiplying and dividing numbers. This can take a good bit of thinking when try to find the answers. But one you get done you can check your answer by knowing whether it is negative or positive.
Just ignore the signs, and go ahead and multiply or divide your numbers.Then, when you finish multiplying or dividing . . .-- If the two original numbers had the same sign, then the answer is positive.-- If the two original numbers had different signs, then the answer is negative.Easy, eh ?
Find the product of their absolute values (without regard for their signs) and then label the product positive. The process is exactly the same if both numbers are negative.
same way except it is a negative quotient.
The quotient of two numbers, X and Y, is X/Y.
The quotient is the result of dividing two numbers. So if you need to find the quotient of 20 and 5, you would divide 20 by 5. That means that your answer (4) would be the quotient.
you use distributive property, basically adding muliplt numbers to find the quotient. quotient being the answer to a division problem.