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In the standard derivation of pendulum characteristics, at least through high school
and undergraduate Physics, an approximation is always made that assumes a small
angular displacement.

With that assumption, the angular displacement doesn't appear in the formula for
the period, i.e. the period depends on the pendulum's effective length, and is
independent of the angular displacement.

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Q: How does the period of a pendulum vary theoretically with angular displacement?
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How does the period of a pendulum difference theoretically with angular displacement and mass of ball for simple pendulum?

According to the mathematics and physics of the simple pendulum hung on a massless string, neither the mass of the bob nor the angular displacement at the limits of its swing has any influence on the pendulum's period.


What are the physical parameters in the investigation of a simple pendulum?

The physical parameters of a simple pendulum include (1) the length of the pendulum, (2) the mass of the pendulum bob, (3) the angular displacement through which the pendulum swings, and (4) the period of the pendulum (the time it takes for the pendulum to swing through one complete oscillation).


How does a pendulums period vary with the length of its mass With Gravitational acceleration?

The length of the pendulum is measured from the pendulum's point of suspension to the center of mass of its bob. Its amplitude is the string's angular displacement from its vertical or its equilibrium position.


How does the period of a pendulum vary theoretically with a angular displacement b mass of bob and c length?

(a) directly with its square root.(b) not at all if it can be considered as a point mass which is significantly greater than the "string". Otherwise corrections are necessary. (c) not if the angle is small. Otherwise corrections are necessary.


How does the period of a pendulum difference theoretically with length for simple pendulum?

The period is directly proportional to the square root of the length.


What is the maths of period of pendulum?

For small swings, and a simple pendulum:T = 2 pi root(L/g) where T is the time for one period, L is the length of the pendulum, and g is the strength of the gravitational field.


What is the pendulum equation?

The period of a simple pendulum is given by the formulaT = 2*pi*sqrt(L/g)where T = periodL = lengthand g = local acceleration due to gravity.Note that this formula is applicable only when the angular displacement of the pendulum is small. For a displacement of 22.5 degrees (a quarter of a right angle), the true period is approx 1% longer : a clock will lose more than 1/2 a minute every hour!


How does the period of a pendulum vary theoretically with (a) length (b) mass of bob and (c) angular displacement?

(a) directly with its square root.(b) not at all if it can be considered as a point mass which is significantly greater than the "string". Otherwise corrections are necessary. (c) not if the angle is small. Otherwise corrections are necessary.


What are the limitation of simple pendulum?

The popular formula for the period of a pendulum works only for small angular displacements. In deriving it, you need to assume that theta, the angular displacement from the vertical, measured in radians, is equal to sin(theta). If not, you need to make much more complicated calculations. There are also other assumptions to simplify the formula - eg string is weightless. The swing of the pendulum will precess with the rotation of the earth. This may not work if the pendulum hits its stand! See Foucault's Pendulum (see link). The motion of the pendulum will die out as a result of air resistance. Thermal expansion can change the length of the pendulum and so its period.


What kind of graph would result if the period of the pendulum T were graphed as a function of the square root of the length of the pendulum?

With a simple pendulum, provided the angular displacement is less than pi/8 radians (22.5 degrees) it will be a straight line, through the origin, with a slope of 2*pi/sqrt(g) where g is the acceleration due to gravity ( = 9.8 mtres/sec^2, approx). For larger angular displacements the approximations used in the derivation of the formula no longer work and the error is over 1%.


Does the time period of oscillation depends on the displacement from the equilibrium position?

If you're thinking about a pendulum but not mentioning it, then no, it doesn't


What are conditions used while calculating time period of simple pendulum?

The time period of a simple pendulum is calculated using the following conditions: Length of the pendulum: The longer the length of the pendulum, the longer it takes for one complete back-and-forth swing. Acceleration due to gravity: The time period is inversely proportional to the square root of the acceleration due to gravity. Higher gravity results in a shorter time period. Angle of displacement: The time period is slightly affected by the initial angle of displacement, but this effect becomes negligible for small angles.