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How does the total time changes as the total distance increases in case of uniformly accelerated motio n?
Wiki User
∙ 13y ago
the formula that ties displacement (you can think of it as distance in a given direction), velocity, time and acceleration (a) is :
s = s0+vt + 1/2at^2
s0 = initial displacement (you can equate to 0, if you start at 0)
vt = starting velocity times time (you can equate to 0 if initial velocity is 0)
s= final displacement
so s=1/2at^2 = (1/2 x a x t x t), so here you end up with a relationship between displacement, acceleration and time. (note: ^2 stands for "to the 2nd power")
Wiki User
∙ 13y ago
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How does the total distance changes as the total time increases in case of uniformly motio?
For uniform motion, distance = velocity*time where uniform implies that the velocity is a constant. Therefore distance = v*time and so, if time increases by t, the distance increases by vt.
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