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â 14y agoEach revolution rolls the truck ahead 1 tire-circumference.
(2 revs per second) x (2.5 meters per rev) = 5 meters per second
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â 14y agoTo convert speed from meters per second (m/s) to revolutions per minute (RPM), you need to know the circumference of the rotating object. Without that information, it is not possible to directly convert mach 0.8 or 272.23 m/s to RPM. RPM is a measure of rotational speed, whereas mach is a unit of relative velocity to the speed of sound.
2 meter circumference rotating 1 revolution per second produces a linear speedof 2 meters per second.The question can be slightly more exciting if you give the diameter of the wheel,or even its radius, instead of its circumference.
imagine standing on a roundabout. f is the number of complete revolutions of the circumference which you make per second. omega on the other hand is the number of times you pass the radial distance per second. as the circumference of a circle is 2(pi)*radius, the number of times you travel a radius within a given time will be 2(pi) times the time to travel the circumference
A point at a distance of x metres from the centre of an object travels through 2*pi*x metres for each revolution. So if the object is rotating at r revolutions per second, the point in question is travels through 2*pi*x*r metres in a second.
There are 1000 meters/second in 1 kilo meters/second
To convert speed from meters per second (m/s) to revolutions per minute (RPM), you need to know the circumference of the rotating object. Without that information, it is not possible to directly convert mach 0.8 or 272.23 m/s to RPM. RPM is a measure of rotational speed, whereas mach is a unit of relative velocity to the speed of sound.
2 meter circumference rotating 1 revolution per second produces a linear speedof 2 meters per second.The question can be slightly more exciting if you give the diameter of the wheel,or even its radius, instead of its circumference.
It equals 9.67 metes per second.
revolutions are angular velocity (w), so you need to know radius (r) to convert to velocity (v) meters per second. not linear velocity. v = wr. For example 30 revs per min is 30/60 revs per second; over a 2 meter radius velocity is 30/ 60 x 2 = 1 meter per second
The velocity of a rotating member can be calculated using the formula v = rĪ, where v is the linear velocity, r is the radius of rotation, and Ī is the angular velocity in radians per second. Multiply the radius of rotation by the angular velocity to find the linear velocity of the rotating member.
18 revolutions = 113.097 radians.
Depends on the diameter of the wheels. Formula should be (5 min)*(60 sec/min)*(3 rev/sec)*(? meters/rev) Where ? meters would be the circumference of the wheels which is pi*diameter
To convert revolutions per minute (RPM) to linear velocity in meters per second (m/s), you need the radius of the rotating object. The linear velocity can be calculated by multiplying 2Ī times the RPM by the radius in meters, and then dividing by 60. The formula is: linear velocity (m/s) = 2Ī * RPM * radius (m) / 60.
Divide the 62,500 miles/second by the circumference (in miles); that will give you the revolutions per second.Note: If you are given the diameter, you can multiply that by pi to get the circumference; if you are given the radius, multiply that by 2 x pi.
imagine standing on a roundabout. f is the number of complete revolutions of the circumference which you make per second. omega on the other hand is the number of times you pass the radial distance per second. as the circumference of a circle is 2(pi)*radius, the number of times you travel a radius within a given time will be 2(pi) times the time to travel the circumference
If a point on the equator of the star was moving at that speed, the star would be rotating at approx 43.5 times a second.
You can solve for revolutions per second using the equation (f = \frac{v^2}{r}), where (f) is centripetal force, (v) is linear velocity, and (r) is radius. Once you know linear velocity, you can calculate revolutions per second by dividing linear velocity by the circumference of the circular path.