v2 = u2 + 2as where v = current velocity, u = initial velocity, a = acceleration, and s = displacement. Taking a = - 9.8 ms-2 v2 = 182 - (9.8 x 11 x 2) = 108.4 v = 10.4 ms-1
There is no change. The bike is moving along a horizontal surface, and only a change in height can change the gravitational PE.
The person's speed is 2 meters per second. The power required for him to accomplish that depends on his weight, on his efficiency of movement, on whether he's moving horizontally or vertically, etc., all of which the question neglects to specify.
It is moving a figure horizontally and/or vertically but keeping it of the same size and orientation.
Expending or using less energy to overcome gravity's pull to move the object,2) better leverage in moving it to a greater height and distance. But first you have to overcome friction using rollers,rope and pulleys...once it starts to move keep going.
15 meters north. the object is only moving away from the original starting place. its not like its moving away and then back again.
20 meters per second
Moving directly straight either horizontally or vertically. As if walking on a straight line.
Moving directly straight either horizontally or vertically. As if walking on a straight line.
There is no change. The bike is moving along a horizontal surface, and only a change in height can change the gravitational PE.
The person's speed is 2 meters per second. The power required for him to accomplish that depends on his weight, on his efficiency of movement, on whether he's moving horizontally or vertically, etc., all of which the question neglects to specify.
Because the bomber is moving quickly, which means that the bomb is travelling quickly forward when it is launched. This would take the bomb way past the target by the time it reaches the ground.
The surface area is the variable to determine how fast an object will be moving when it reaches terminal velocity.
It is moving a figure horizontally and/or vertically but keeping it of the same size and orientation.
Yes, but only for an instant. Throw a rock or a baseball straight up. After a while, it reaches its maximum height, stops moving up, and starts moving down. From the time it leaves your hand, its acceleration is constant. But at the very top of the arc, where it's changing from moving up to moving down, at that instant, it has zero velocity.
Because the rain is moving vertically downward and the car is moving horizontally that's why the motion of the rain is slant.
Expending or using less energy to overcome gravity's pull to move the object,2) better leverage in moving it to a greater height and distance. But first you have to overcome friction using rollers,rope and pulleys...once it starts to move keep going.
Still accelerating til it hits earth. ====================================== The height from which she dropped the ball is irrelevant. In any case, the ball was most likely moving at the greatest speed just as it hit the ground. The answer to the question is: zero.