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5
84 feet tall
35 feet tall.
Using trigonometry its height is 12 feet
The height of the flagpolle is 26.25 feet
5
84 feet tall
When the light source is directly over it or at night.
They both have the same tangent ratio so let the flagpole be x: x/60 = 18/24 Multiply both sides by 60: x = 1080/24 x = 45 feet
35 feet tall.
Using trigonometry its height is 12 feet
The height of the flagpolle is 26.25 feet
The lenght of the shadow will be 12.6 ft
Not enough information has been given to solve this problem such as: What is the angle of elevation?
I think this question is about similar shapes. To answer this divide the height of the tree, 5ft, by the shadow cast by it, 3 ft. This will give you the scale factor. To then find the answer, times the scale factor by the shawdow cast by the nearby tree, and will find your answer in ft. Hope this helped.
25
The flagpole is 15 feet in height. At any given moment of the day, all of the shadows that are cast by objects will have lengths that are equally proportional to the actual height of the object. Since Blake's shadow is 20 feet long and he is actually 5 feet tall, actual heights are going to be one fourth (1/4) of the length of any shadow they cast, at that specific time of the day. 60 x (1/4) = 15 feet.