They both have the same tangent ratio so let the flagpole be x:
x/60 = 18/24
Multiply both sides by 60:
x = 1080/24
x = 45 feet
The man is twice as high as his shadow. Therefore, the tree must also be twice as high as its shadow, which would make the tree 40 feet tall.
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
It works out as 12 feet and 4 inches in height
The man is 9 feet away from the street light.
As the sun is far enough away, the rays of light are effectively parallel. This produces similar triangles with the ratio of sides the same in each case. As the shadow of the post is 12 ft and the shadow of the tree is 24 ft, the sides of the triangle of the tree are double that of the post. Assuming the post is parallel to the tree, the tree's height is twice the height of the post → tree = 12 ft × 2 = 24ft high.
1. How high is a flagpole that casts a shadow of 45 ft at the same time a woman 5.5 ft tall casts a shadow 10 ft?
First, find the ratio of fencepost-height : shadow which is 1.6 : 2.6 . This can also be written as a fraction, 1.6/2.6 . Then, multiply the flagpole's shadow by this ratio: 31.2 x 1.6/2.6 = 19.2 The flagpole is 19.2m high. The trigonometry way: On the imaginary right angled triangle formed by the fencepost and its shadow, let the angle at which the hypotenuse meets the ground = θ sinθ = 1.6/2.6 sinθ = /31.2 x/31.2 = 1.6/2.6 2.6x = 31.2 * 1.6 = 49.92 x = 19.2 The flagpole is 19.2m high.
Not enough information has been given to solve this problem such as: What is the angle of elevation?
Just over 228 feet.
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
1.8 meters. The ratio of object to shadow is 10:6. Therefore if the object is 3, the shadow is 1.8 ( 6/10x3).
56.25 feet
Divisibles, the 6 foot man would cast a shadow 2 feet long.
3.4
Let the length of the shadow be x and change all the feet into inches to avoid fractions. 780/x = 70/246 Multiply both sides by x: 780 = 70x/246 Multiply both sides by 246: 191880 = 70x Divide both sides by 70: x = 2741.142857 inches and when divided by 12 = 228.4285571 feet So the length of the shadow is about 228 feet.
Objects do cast shadows at higher altitudes in the same way they do on the ground; however, the shadow may not be visible due to the lack of contrast against the sky. Additionally, the position of the sun in the sky and the angle at which light is hitting the object can also affect the visibility of the shadow.
It works out as 30 feet in height