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Maybe you mean y2y8y6 = 2*8*6 *y^3 = 96y^3. This is not 1. Otherwise, I do not know what you could mean by Y 2y8y 6.
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How is Y-2y8y-6 equivalent to 1?
y-2y8y-6 1y-2y8y-6 1y-6y-6 5y-6 1y
Y-2y8y-6 is equivalent to?
1. the answer is 1.
What equation describes y-6-4(x plus 1)?
If you mean y-6 = -4(x+1) then it is a straight line equation equivalent to y = -4x+2 when completed whereas the slope is -4 and the y intercept is 2
Is x equals -1 is a solution of x plus y equals 4 x-y equals 6?
If for x = -1 we find the same value of y in both equations, then x = -1 will be a part of the solution of the system.Let's suppose that x = -1 is the x-coordinate of the solution of the given systemx + y = 4x - y = 6.x + y = 4-1 + y = 4-1 + 1 + y = 4 + 1y = 5x - y = 6-1 - y = 6-1 - 6 + y - y = 6 - 6 + y-7 = ySince we have two different values for y, we say that x = -1 is not a part of the solution for the given system.
How do you find the slope intercept and standard forms of a line when the y-intercept is -5 and the coordinates given are -1 and -1?
here is the formula... y-y1=m(x-x1) solution.. y-(-1)=m(x-(-1)) m= (0,-5) (-1,-1) -1-5/-1-0= -6/-1 or +6/6 y-(-1)=6(x--1) y+1=6(x+1) y+1=6x+6 y=6x+6-1 y=6x+5 form of y=mx+b y=6x+5 form of Ax+By+C=0 6x-y+5=0
How is Y-2y8y-6 equivalent to 1?
y-2y8y-6 1y-2y8y-6 1y-6y-6 5y-6 1y
Y-2y8y-6 is equivalent to?
1. the answer is 1.
What equation describes y-6-4(x plus 1)?
If you mean y-6 = -4(x+1) then it is a straight line equation equivalent to y = -4x+2 when completed whereas the slope is -4 and the y intercept is 2
What 3 inequalities that are equivalent to y-3?
6
Is x equals -1 is a solution of x plus y equals 4 x-y equals 6?
If for x = -1 we find the same value of y in both equations, then x = -1 will be a part of the solution of the system.Let's suppose that x = -1 is the x-coordinate of the solution of the given systemx + y = 4x - y = 6.x + y = 4-1 + y = 4-1 + 1 + y = 4 + 1y = 5x - y = 6-1 - y = 6-1 - 6 + y - y = 6 - 6 + y-7 = ySince we have two different values for y, we say that x = -1 is not a part of the solution for the given system.
How do you find the slope intercept and standard forms of a line when the y-intercept is -5 and the coordinates given are -1 and -1?
here is the formula... y-y1=m(x-x1) solution.. y-(-1)=m(x-(-1)) m= (0,-5) (-1,-1) -1-5/-1-0= -6/-1 or +6/6 y-(-1)=6(x--1) y+1=6(x+1) y+1=6x+6 y=6x+6-1 y=6x+5 form of y=mx+b y=6x+5 form of Ax+By+C=0 6x-y+5=0
Points of y equals -2x plus 6 and x equals 1?
Given: y = -2x + 6 x = 1 y = -2(1) + 6 y = 4 I believe this is what you meant. Possibly you meant: y = -2x + 6 + x = 1 Then you would get y = 1 -x + 6 = 1 x = 5
What is 6 equals y - 7?
-1
Is Y over Y irrational?
No because y/y is equivalent to 1 which is a rational number
If y equals 4x-6 find y if x equals 1?
y=4x-6 and x=1 Just replace the x in the first equation with 1 and solve. y=4(1)-6 y= (-2)
What two numbers have a product of negative 5 and a sum of negative 2?
Let the 2 numbers be 'x' and 'y': then, x + y = -2 => x = -2 -y -- (1) Also, x * y = -5 -- (2) Put (1) in (2), we have (-2 -y) * y = -5 -2y -y^2 = -5 y^2 + 2y - 5 = 0 We cannot factorize these numbers easily, so we will have to use the Quadratic Formula to solve this: y=( -b ± √( b^2 - 4ac )) / ( 2 * a ) =(-2 ± √( 2^2 -4*1*-5 )) / (2 * 1 ) =(-2 ± √(24)) / 2= -1 ± 2 * √(6) / 2=-1 ± √(6) We can substitute these values into x=-y-2: x=-(-1 + √(6)) - 2 = 1 - √(6) - 2= -1 - √(6) x=-(-1 - √(6)) - 2 = 1 + √(6) - 2= -1 + √(6) Therefore: x=-1-√(6) y=-1+√(6) OR x=-1+√(6) y=-1-√(6)
How do you find the slope of y equals 6-x?
y = 6 - xThe slope is -1 .The y-intercept is y=6 .
