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find the diagonal method of two digit number and three digit number
The answer is 4. You get the answer by trying the example of the largest two digit number, 99. 99 x 99 = 9801. This has four digits, so you can't get more digits than this by multiplying two two digit numbers. * * * * * True, but you CAN have fewer: 10*10 = 100, which is only three digits! 1490 of the 8100 2 digit x 2 digit multiples have products of 3 digits, the rest have 4 digit products.
There is no difference in the procedure.
They are the same because they are both multiplication. They also can be the same if the two digit number times by the one digit number equals a three digit number. They are different because the 3 digits number will obviously produce a higher product.
6 times
Four. (100 x 10 = 1,000)
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111 111 111 If you multiply 12345679 by any two digit number* where the first digit is less than 9 and the sum of the digits is 9 (eg 36), the answer will consist of a single digit repeated 9 times. This will be the first digit of the two digit number plus 1 (eg multiplying by 36 will create an number consisting of only the digit 3+1 = 4: 12345679 x 36 = 444 444 444). *Multiplying by 9 is multiplying by the "two" digit number "09", giving an answer consisting of the single digit 0+1 = 1 repeated.
find the diagonal method of two digit number and three digit number
11, 47, and 71
The answer is 4. You get the answer by trying the example of the largest two digit number, 99. 99 x 99 = 9801. This has four digits, so you can't get more digits than this by multiplying two two digit numbers. * * * * * True, but you CAN have fewer: 10*10 = 100, which is only three digits! 1490 of the 8100 2 digit x 2 digit multiples have products of 3 digits, the rest have 4 digit products.
Multiply the three-digit number by the one's digit, or last digit, of the two-digit number. That is your first part. Now multiply by the second-to-last digit, or ten's digit, and multiply the result by 10. That is your second part. Add the two parts and that is your answer.
If two of the prime factors are 2 and 5, the last digit of the number will be zero.
It should be obvious (it is, isn't it? am I expecting too much of today's educational system?) that the largest possible result of multiplying two two digit numbers is 99x99 = 9801, which has four digits, and the smallest possible result is 10x10 = 100, which has three digits.