By any multiples of 21
The numeral '21' is evenly divisible by 21, 7, 3, and 1.
They're both divisible by 1,3,7, and 21.
There is nothing that is divisible in 37 and 21. Because 37 is a prime number. However, 21 is divisible by 3 and 7.
Because 21 is a multiple of 1, 3, 7 and 21.
Because 21 is divisible by numbers other than 1 and 21. 21 is divisible by 1, 3, 7, 21
a number is divisible by 12 if the number is also divisible by both 3 and 7. You mean a number is divisible by 21 if it is divisible by 3 and 7.
No, it is not.
No, it is not.
No, it is not.
To show that the product of 56 and 39 is exactly divisible by 21, you can check if both numbers are divisible by the prime factors of 21, which are 3 and 7. Since 56 is divisible by 7 (56 ÷ 7 = 8) and 39 is divisible by 3 (39 ÷ 3 = 13), their product will also be divisible by both 3 and 7. Therefore, 56 x 39 is divisible by 21.
Both 21 and 32 are divisible by 1. Additionally, 21 is divisible by 3 and 7, while 32 is divisible by 2, 4, 8, and 16. However, they have no common divisors other than 1, making them relatively prime.
They are members of the infinite set of numbers of the form 21*k where k is an integer.