4x(7+9)= 28+36=64.
The expression for 7 times the sum of ( c ) and 2 can be written as ( 7 \times (c + 2) ). This means you first add 2 to ( c ), and then multiply the result by 7. Therefore, the final expression is ( 7(c + 2) ).
It is 9*(n + 7)
14/3 + 4 = 14/7 = 2
The algebraic expression for 7 decreased by 4 times a number can be written as ( 7 - 4x ), where ( x ) represents the number. This expression captures the operation of subtracting four times the variable from seven.
the sum of -2 and 6 and 7 is (-2+6+7)
The expression for 7 times the sum of ( c ) and 2 can be written as ( 7 \times (c + 2) ). This means you first add 2 to ( c ), and then multiply the result by 7. Therefore, the final expression is ( 7(c + 2) ).
3(y+7)
To find 4 times the sum of y and 7, you first calculate the sum of y and 7, which is y + 7. Then, you multiply this sum by 4 to get the final result. Therefore, the expression for 4 times the sum of y and 7 is 4(y + 7), which simplifies to 4y + 28.
It is 9*(n + 7)
7 * (c + 2) = 7 * c + 14
14/3 + 4 = 14/7 = 2
The algebraic expression for 7 decreased by 4 times a number can be written as ( 7 - 4x ), where ( x ) represents the number. This expression captures the operation of subtracting four times the variable from seven.
4(7-1)
the sum of -2 and 6 and 7 is (-2+6+7)
5(a+b)-7
7(n+3)
Four multiplied by -7 is -28.