Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
17 goes in 119 7 times.
2 *5y
Call your number 10x + y. x = y + 2 and 10x + y = 4 + 6(x + y) Substitute y + 2 for x: 10(y + 2) + y = 4 + 6((y + 2) + y) This simplifies to 10y + 20 + y = 4 + 6y + 12 + 6y, ie 20 - 16 = 12y - 11y so y = 4 and x = 6 Your number is 64, which is indeed 4 more than the sum of its digits.
y=mx+b y = -(7/4)x + 7
3(y+7)
Algebraic expressions are useful for translating problems into the language of mathematics. An algebraic expression for the problem "6 times the sum of 4 and y" would be: 6(4+y) = 24 + 6y.
5(x^2 + y)
6(4+y)
Y = 4 (x+8)
It could be: 6x+y+4
Depending on where exactly the commas are in the statement, the equation will be different. Based on the exact punctuation and wording of the question, the equation is: 3a+4b=(x+y)/7-12
4 + y.
In an addition sum, if the missing number is the first number, for example, x + 5 = 10, then to find x, perform the sum 10 - 5, producing the solution x = 5. In a subtraction sum, if the missing number is the second number, for example, 7 - y = 4, then to find y, perform the sum 7 - 4 = 3, production the solution y = 3.
x + y = 28 x*y = 7 x=7/y replacing X in eq 1 7/y+y=28 y^2 - 28y + 7 = 0 using above solutions find the reciprocal and sum -- Dhruv
To find 2 times the sum of x and y, you first need to calculate the sum of x and y by adding the two variables together. Once you have the sum, you multiply it by 2 to get the final result. In mathematical terms, the expression for 2 times the sum of x and y can be written as 2(x + y).
Consider sum of two number to be x+y=6 and x/y=7. On substitution, it is found that x=4.42 and y=1.58.