it is the concentration of H3O+ times the concentration of OH-
all coniditions
[OH-]=[acidic medium]. kw /[basic medium]KOH At const temp and pressure Kw/KOH=const.=K1=[H+][In-]/[HIn] pk1 is generally termed as indicator const.
1000 kw
About 0.1 kW for a kitchen fridge.
1000 watts
487.3044 kW
Kc is the constant for concentration and Kw is the constant for water. Kc[h20] = [OH-][H+] which becomes Kw= [OH-][H+]
Kw is called the water autoprotolysis constant or water autoionization constant
Kw is the ionisation constant for water at 25°C which value is 1.0x10^-14. (chemistry)In water at any pH the equilibrium state Kw is defined by and equal to the 'ion product':Kw = [H3O+]*[OH-] = 1.0*10-14at room temperature 25°C
The ionization constant of water at 250C, its value is 1x10-14 A: ion-product constant of water.
1.0*10^-14 No Units
Kw of water changes when temperature changes. Usually the temperatue is 298K , Kw is a constant:10exp-14, so when you test pH, the (H+) is less than 10exp-14.
[OH-]=[acidic medium]. kw /[basic medium]KOH At const temp and pressure Kw/KOH=const.=K1=[H+][In-]/[HIn] pk1 is generally termed as indicator const.
dissociation of acid in water: A + H2O <-> A- + H3O+ with dissociation constant Ka = [A-][H3O+]/[A][H2O] = [A-][H3O+]/[A]. dissociation of base in water: B + H2O <-> HB+ + OH- with dissociation constant Kb = [HB+][OH-]/[B][H2O] = [HB+][OH-]/[B] dissociation of water in itself: 2H2O <-> H3O+ + OH- with dissociation constant Kw = [H3O+][OH-]/[H2O]^2 = [H3O+][OH-] where [H2O] has been ommitted because it is a pure liquid. substituting relations for Ka and Kb into Kw gives: Kw = [H3O+][OH-] = (Ka[A]/[A-])(Kb[B]/[HB+]) = KaKb where [A] = [HB+] and [B] = [A-].
Well, I have a 2.5 kw pvground mounted system, but I never imagined that it would `power my house'. Truth be told, I doubt that 2.5 kw will barely boil an electrickettle. The real benefit is the cumulative effect of the constant day time output of the panels.
A breaker protects the wire size of the feeder that is connected to it. The amperage of the load must be found. Without a voltage stated the amperage from the wattage given can not be calculated. The equation for amperage when the kw is given is A = kW x 1000/1.73 x volts x pf. The pf constant to use is .9.
i dnt kw the answer can u help m
1TR = 3.5 KW 1TR = 3.5 KW