How long to fall 300 feet?

Answer 1

position final = position initial + (speed initial)(time) + .5(acceleration)(time^2)

0=300 + 0(x) +.5(-9.807)(x^2)

0=300 + 0 + -4.9035(x^2)

-300=-4.9035(x^2)

-300 / -4.9035 = x^2

61.18 = x^2

x = 7.82 seconds

That is to assume that the initial speed is 0.

This is incorrect.

The initial distance is in feet, 300 feet, but the rate of acceleration is in meters per second squared, (-9.807 meters per second squared).

To get the correct answer, the units of measurement must match, either feet or meters.

The correct answer is 4.32 seconds.