50
Calcium chloride is a compound. Assuming the 50 m actually means 50 mol, this number at the beginning is a distractor and does not impact the problem.
To find the moles of HCl, first calculate the millimoles of HCl in 50 mL: 4.0 mol/L * 50 mL = 200 mmol. Then convert millimoles to moles by dividing by 1000: 200 mmol / 1000 = 0.2 moles of HCl. Therefore, there are 0.2 moles of HCl in 50 mL of 4.0 M HCl.
Use this fomula: (m/M)*NA in which m is mass in gram (g), M is molar mass (g/mol) and NA is the Avogadro number (mol^-1)
The answer is 0,3422 grams.
1.52 mol/L * 1.00 L = 1.52 mol
50 mm = 0.05 m.
.5 m
You would need to measure 400 mL of the 0.250 M NaCl solution to obtain 0.100 mol of NaCl. This is calculated by dividing the amount of moles needed by the concentration of the solution: 0.100 mol / 0.250 mol/L = 0.400 L = 400 mL.
0.535 g NH4Cl in 50 ml :concentration is [ 0.535 g / 53.5 g/mol] = 0.100 mol in 50 ml = 0.100 mol / 0.050 L =2.0 mol/L NH4Cl = 2.0 M NH4ClpH = pKz(NH4+) - log [NH4+]/[NH3] 1) = 9.24 - log[2.0]/[0.1] = 9.24 - 1.30 = 7.94 = 7.9Note: this is actually out of the range of a buffer and of the Henderson-Hasselbalch equation 1) so the the outcome is only indicative.
50 m = 0.05 kmTo convert from m to km, divid by 1000.
50 000 m = 50 kmTo convert from m to km, divide by 1000.
0.5 m