6 tiles; you'll have 2/3 of one tile left over.
There are 144 18 square inch tiles in an area of 18 square feet.
You will need 44 six inch tiles to cover 11 square feet.
About 197 (196.875) 16" x 16" tiles will feet in that area.
120 tiles because the area of the floor is 30 square feet. If you can fit four tiles into one square foot then you could fit 120 tiles in 60 square feet.
To determine how many 1.6-inch tiles you need to cover 168 square feet, first convert the tile size to square feet. A 1.6-inch tile is ( \frac{1.6}{12} ) feet, which is approximately 0.1333 feet. The area of one tile is ( 0.1333 \times 0.1333 \approx 0.0178 ) square feet. To find the number of tiles needed, divide the total area by the area of one tile: ( \frac{168}{0.0178} \approx 9444 ) tiles. Thus, you need approximately 9,444 tiles to cover 168 square feet.
The number of concrete tiles in a square depends on the size of the tiles. For example, if you have 12-inch by 12-inch tiles, one square foot (which is 12 inches by 12 inches) would require one tile. If the tiles are smaller, like 6-inch by 6-inch, you would need four tiles to cover one square foot. To determine the exact number, you can divide the area to be covered (in square feet) by the area of one tile (in square feet).
Is this a trick question? A 12 inch tile has an area of 1 square foot. So to cover 294 square feet you would need 294 tiles!
Floor area = 12 ft x 18 ft = 216 square feet. There are 4 six-inch square tiles needed for each square foot, so 864 tiles are needed.
5,184 2-square-inch tiles are needed.
The answer depends on the shape of the 30 square feet area. If it is in the form of a strip that is 5 inches wide and 72 feet long and you don't want mosaics with little offcuts, then you will require 144 tiles.
You would need 138 tiles to cover 115 square feet with 12-inch tiles. To calculate this, divide the total square footage (115) by the area of one tile (1 square foot for a 12-inch tile). So, 115 (sq ft) / 1 (sq ft per tile) = 115 tiles.
875 24-inch tiles.