Assuming no gap for grouting the spaces between the tiles, the area is 18 times 30 = 540 square inches, and as each tile measure 1 square inch, the number needed is 540.
However, that's just the answer to the mathematical question. For a real - practical - answer you can assume that the tiles will be spaced approximately one-eighth of an inch apart, which means that 8 tiles will cover 9 linear inches. this means that you will need 16 tiles in one direction and 27 in the other. That is a total of 432 - which is quite a financial saving.
49 tiles
157 18 by 18 tiles are needed to cover 352 square feet.
128.2 tiles
226 tiles
25 geinus
The amount of tiles needed to cover a floor will depend on the size of the floor.
49 tiles
157 18 by 18 tiles are needed to cover 352 square feet.
It depends on how big the tiles are.
128.2 tiles
226 tiles
25 geinus
The answer will depend on the size of the tiles.
i cant give you an answer with out know how big the tiles are sorry :(
1540
616 3x6 inch tiles are needed to cover exactly 77 square feet.
2400 tiles if you don't get any extra