Assuming no gap for grouting the spaces between the tiles, the area is 18 times 30 = 540 square inches, and as each tile measure 1 square inch, the number needed is 540.
However, that's just the answer to the mathematical question. For a real - practical - answer you can assume that the tiles will be spaced approximately one-eighth of an inch apart, which means that 8 tiles will cover 9 linear inches. this means that you will need 16 tiles in one direction and 27 in the other. That is a total of 432 - which is quite a financial saving.
The amount of tiles needed to cover a floor will depend on the size of the floor.
It depends on how big the tiles are.
157 18 by 18 tiles are needed to cover 352 square feet.
i cant give you an answer with out know how big the tiles are sorry :(
The answer will depend on the size of the tiles.
236 18-inch tiles.
2400 tiles if you don't get any extra