616 3x6 inch tiles are needed to cover exactly 77 square feet.
118
It will require a minimum of 1,462 tiles. That number will cover about 1,850.34 square feet.
You will need at least 192 tiles.
To find out how many 3x6 tiles are needed to cover 800 square feet, first calculate the area of one tile. A 3x6 tile has an area of 18 square inches, which is 1.25 square feet (since 144 square inches = 1 square foot). Divide 800 square feet by 1.25 square feet per tile, which equals 640 tiles. Therefore, it will take 640 tiles to cover 800 square feet.
If your tiles are 12 inches x 12 inches you would need 144 of them.
192 tiles
1296 Tiles
157 18 by 18 tiles are needed to cover 352 square feet.
500/1.78 = 281 tiles
118
About 17.
10
Each tile covers 4 square feet. You will need 24.75 tiles to cover the area.
If the tiles are 1 foot squares, it will take 1,650 of them to cover 1,650 square feet. If the tiles are 16 inch square (1-1/3 square feet, each), then it would take 1,238 tiles.
It will require a minimum of 1,462 tiles. That number will cover about 1,850.34 square feet.
480
20