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Q: How many 20' strings of lights are needed to go around the walls of a 34' hexagon tent?
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How many strings of lights needed to decorate a room that is 25.5 yards long and 32 yards wide if a string of lights is 5 yards?

A room that is 25.5 yards * 32 yards has a perimeter of 2*(25.5 + 32) = 2*57.5 = 115 yards. If each string of lights is 5 yards long, the number of strings required is 115/5 = 23.


How many line segments are needed to draw a hexagon?

6


How many rhombuses are needed to make a figure that is congruent to a hexagon?

2 rhombuses and 2 triangles


How many straight lines are needed to divide a regular hexagon into six identical triangles?

4


Is it possible to construct a hexagon using only a straightedge and a compas?

Yes First construct an equilateral triangle: Draw the base side of the triangle and label the ends A and B - this will be the first side of the hexagon. Set the compass to the length of the side. With the compass on one end of the line (point A), draw an arc to one side of the line (roughly near the middle). With the compass on the other end of the line (point B), draw a second arc to intersect the first arc (call this point O) - this is the apex of the triangle. Normally when constructing the triangle side OA and OB would be drawn in, however as a hexagon is being constructed only the location of O is needed. This point O will be the centre of the hexagon. Now construct 4 further equilateral triangles: For the first use OB as the base (the actual line is not needed, just its endpoints), construct its apex C and using the straight edge join B to C. For the next, use OC as the base, construct its apex D and join C to D Then use OD, construct apex E and join D to E Finally using OE, construct apex F and join E to F. The hexagon can now be completed by joining F to A.

Related questions

How many strings of lights needed to decorate a room that is 25.5 yards long and 32 yards wide if a string of lights is 5 yards?

A room that is 25.5 yards * 32 yards has a perimeter of 2*(25.5 + 32) = 2*57.5 = 115 yards. If each string of lights is 5 yards long, the number of strings required is 115/5 = 23.


What is the fewest number of strings needed to string a tennis racket?

Two strings are needed to string a tennis racket. The length of the string is to be about 11 to 12 meters.


What are the different strings called that are needed for a 12 string guitar?

The strings are paired in courses, but they only have four or five courses of strings rather than six. They are called stanford strings.


How many triangles are needed to make a figure that is congruent to a hexagon?

6


How many line segments are needed to draw a hexagon?

6


How many shapes are needed to make a figure congruent to a hexagon?

4 sqaure


What bulb is needed for dipped lights on a 05 Honda accord?

dipped lights? What is dipped lights?


How many rhombuses are needed to make a figure that is congruent to a hexagon?

2 rhombuses and 2 triangles


How many straight lines are needed to divide a regular hexagon into six identical triangles?

4


How many endpoints are needed to draw six line segments?

12 of then but if they are joined together in the form of a 6 sided hexagon then 6 endpoints are needed.


What lights are needed for boating at night?

Head lights, port, starboard and stern lights (on 28' pontoon boat).


How many straight lines are needed to divide a regular hexagon?

That depends how many sections you wish to divide it into.