1200 sq ft = 1200*144 = 172800 sq inches.
Each tile = 20*20 = 400 sq inches
So minimum number of tiles required = 432.
However, this assumes that the shape to be tiled is well behaved and that there is no wastage.
20" = 2.78 square feet. Now divide the area of the tiles into the area of the room. 140/2.78 = 51 tiles
comes out to about 126 tiles, but would get 140 depending on amount of cuts there are and can always take the extras back.
20X20" tiles are 1.67'X1.67' giving a total sq ft per tile of 2.8 s/f 100 tiles would cover 280 sq feet so looks like 97 tiles gets you to 272. we always recommend about 5-7% overage to allow for a broken tile or a bad cut.
A A 12x12 sq feet tile covers 144 sq feet. So to cover 1200 sq feet you will need 1200/144 = 8.3 or 9 tiles.
675 of them. Get extra for breakage.
1070 square feet is 154080 square inches. (1 square foot is 12x12 or 144 square inches.)a 20x20 inch tile is 400 square inches.So the question could be restated as "how many 400 square inch tiles does it take to cover 154080 square inches?"154080 / 400 = 385.2
440 sq feet = 440 x 144 sq inchesanswer = 440 x 144/ (20 x 20) = 440 x 144 /400 = 1.1 x 144 = 158.4 tiles ~ 159 tiles
Assuming they are 20 by 20 inches, then the area of a tile is 400 feet2/144. 200 feet2/(400 feet2/144) = 72
Just multiply 20 by 20 to find that each tile has 400 square feet to it. Then divide 1000 by 400 to find that you'll need 2.5 tiles -- so you should buy three.
Tiles that are two feet on a side cover 4 square feet. 378 of them cover 1512 square feet.
It depends on how big the tiles are.
76.6 tiles