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- first convert meter to cm.
- the relation 1 m=100 cm.
- 4.5 meter =45 cm.
- comparing ratios 25 cm : 45 cm
- ratio becomes 5 :9
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∙ 9y ago
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How many 25 cm lengths in 4 and a half meters?
18
How many millimetres are in to and a half cm?
25 mm
A right triangle has legs with lengths of 25 cm and 37 cm what is the length of the hypotenuse?
The length of the hypotenuse is: 44.65 cm
What is the area of a square with side lengths of 5cm?
Area = 5*5 = 25 square cm
What are the diagonal lengths of an isosceles trapezoid whose longest parallel side is 25 cm with a height of 18 cm and an area of 315 square cm showing all work leading to the answer?
Let the other parallel side be x and then use Pythagoras to find diagonal lengths: Area: 0.5*(25+x)*18 = 315 sq cm Other parallel side: x = (315*2)/18 -25 = 10 cm Two right angle triangles can be formed with bases of 17.5 and heights of 18 cm Using Pythagoras: 17.5square+18squared = 630.25 and its sq rt is 25 to nearest integer Therefore the diagonal lengths are: 25 cm to the nearest whole number
How many 25 cm lengths in 4 and a half meters?
18
How many millimetres are in to and a half cm?
25 mm
How many 25 centimeter lengths can be cut from 1 meter?
One meter is 100 cm, you do the math.
A right triangle has legs with lengths of 25 cm and 37 cm what is the length of the hypotenuse?
The length of the hypotenuse is: 44.65 cm
How many 25 cm lengths can be cut from 1 m?
4
How many lengths of wire 45 cm long could be cut from a roll four and a half meters?
4.5 meters = 450 cm 450/45 = 10 pieces
Is it possible to construct a triangle with side lengths 12 cm 15 cm and 25 cm?
a scalene triangle is a triangle with three differant sides
How many 30-cm lengths can be cut from a 3-meter length?
1m = 100 cm so 3m = 300 cm300 cm/60 cm = 5 lengths.
What is the area of a square with side lengths of 5cm?
Area = 5*5 = 25 square cm
A right triangle has legs with lengths of 25 cm and 37 cm - what is the length of the hypotenuse?
This right triangle has a hypotenuse of: 44.65 cmFor A+ its 45
What are the diagonal lengths of an isosceles trapezoid whose longest parallel side is 25 cm with a height of 18 cm and an area of 315 square cm showing all work leading to the answer?
Let the other parallel side be x and then use Pythagoras to find diagonal lengths: Area: 0.5*(25+x)*18 = 315 sq cm Other parallel side: x = (315*2)/18 -25 = 10 cm Two right angle triangles can be formed with bases of 17.5 and heights of 18 cm Using Pythagoras: 17.5square+18squared = 630.25 and its sq rt is 25 to nearest integer Therefore the diagonal lengths are: 25 cm to the nearest whole number
What is half of 0.5 centimeters?
25
