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18
25 mm
The length of the hypotenuse is: 44.65 cm
Area = 5*5 = 25 square cm
Let the other parallel side be x and then use Pythagoras to find diagonal lengths: Area: 0.5*(25+x)*18 = 315 sq cm Other parallel side: x = (315*2)/18 -25 = 10 cm Two right angle triangles can be formed with bases of 17.5 and heights of 18 cm Using Pythagoras: 17.5square+18squared = 630.25 and its sq rt is 25 to nearest integer Therefore the diagonal lengths are: 25 cm to the nearest whole number