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How many 3-digit numbers can be made by using the numbers 1 2 3 4 5 6 7 9?
Updated: 11/1/2022
Wiki User
∙ 13y agoBest Answer
You have 8 numbers, and you are choosing 3. This is written as 8c3 and is computed like this:
[8!] / [ (3!) (8-3!)] = 8! / (3! * 5!) = (8*7*6*5*4*3*2*1) / (3*2*1 * 5*4*3*2*1)
Canceling out, you get (8*7*6)/(3*2*1) = 8*7 = 56 ■
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∙ 13y agoThis answer is:
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