this is impossible
The answer is 10C4 = 10!/[4!*6!] = 210
24
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.
Without repeating any of the digits: 4*3*2*1 = 24 If repeated digits are allowed, then 4*4*4*4 = 256
There are 53 = 125 of them. 111, 112, 113, 114, 115, 121 etc.
Without repeating any, six. 12, 13, 21, 23, 31, 32
The answer is 10C4 = 10!/[4!*6!] = 210
There are 55 = 3125 of them.
999
24
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.
0 you can only have 3 layers since you have only 3 numbers so without repeating you would only have 3 layers
Without repeating any of the digits: 4*3*2*1 = 24 If repeated digits are allowed, then 4*4*4*4 = 256
120 5-digit numbers can be made with the numbers 12345.
first A prime number (or a prime) is a natural number greater than 1 that has no positive divisors other than 1 and itself so 1 isnt a prime primes are 2 3 5 7 11 13 17 etc now by repeating digits if you mean the 1's in 11 then stop at 7 if you mean repeating a digit as in the tens spot of 11 and 13 stop at 11 and 3 and 13 are repating the 3 location....etc
The first digit can be any one of 1, 2, 3, 4 or 5. So you can choose the first digit in 5 ways. Having done that, you have only four unused digits. So you can chosse the second digit in 4 ways. Now then you have only three digits left so the third digit can be chaosen in 3 ways and so on. Total number of ways: 5*4*3*2*1 = 120
There are 53 = 125 of them. 111, 112, 113, 114, 115, 121 etc.