From {1, 2, 3, 4} there are two prime numbers (2, 3} which can go in the hundreds position, which once chosen allows 3 possible choices for the tens digit and a further 2 possible choices for the units digit, giving 2 x 3 x 2 = 12 possible numbers.
A composite number.
If you consider whole numbers, the largest 5 digit number with repetition is 99999 the smallest 4 digit number without repetition is -9876 Their difference is 99999 - (-9876) = 99999 + 9876 = 109875.
That depends entirely on the number of digits each number is permitted to have !
It is the prime factorisation of the desired number.
I'm not confident that my calculations are correct; I'm withdrawing my attempt. My guess is that if repetition of numbers is allowed, and if the order of the numbers is important (663 is distinct from 366) then there are 216 possibilities. With repetition but no particular order, I think the number is 186 possibilities.* * * * *Combinatorial theory is based on the premise that the order of the numbers does not matter. So that 234, 243, 432 are all the same.If no repetition is permitted, there are 6C3 = 6*5*4/(3*2*1) = 20 combinations.If repetition is allowed,there are a further 6*5 = 30 combinations with a pair and a singletonand another 6 triplets.All in all 56 combinations.Although NOT strictly part of the answer, the number of permutations (order DOES matter), without repeat, are6*5*4 = 120and finally, if repeats are allowed, the number is 6*6*6 = 216 as in the previous answer.However, remember that "combination" locks are a misnomer and in mathematics the order does not matter in combinations.
With repetition, there are 86 ( = 262144) such numbers. Without repetition, there are still 8!/2! = 20160.
A composite number.
9999-1023 = 8976
As a number, 13 hundred is 1300.
If you consider whole numbers, the largest 5 digit number with repetition is 99999 the smallest 4 digit number without repetition is -9876 Their difference is 99999 - (-9876) = 99999 + 9876 = 109875.
Phone numbers are not permitted on this site.
That depends entirely on the number of digits each number is permitted to have !
It is the prime factorisation of the desired number.
I'm not confident that my calculations are correct; I'm withdrawing my attempt. My guess is that if repetition of numbers is allowed, and if the order of the numbers is important (663 is distinct from 366) then there are 216 possibilities. With repetition but no particular order, I think the number is 186 possibilities.* * * * *Combinatorial theory is based on the premise that the order of the numbers does not matter. So that 234, 243, 432 are all the same.If no repetition is permitted, there are 6C3 = 6*5*4/(3*2*1) = 20 combinations.If repetition is allowed,there are a further 6*5 = 30 combinations with a pair and a singletonand another 6 triplets.All in all 56 combinations.Although NOT strictly part of the answer, the number of permutations (order DOES matter), without repeat, are6*5*4 = 120and finally, if repeats are allowed, the number is 6*6*6 = 216 as in the previous answer.However, remember that "combination" locks are a misnomer and in mathematics the order does not matter in combinations.
Two hundred thousand as a number is 200,000
9888
1000000000 or, if negative numbers are permitted, then -9999999999