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I'm not confident that my calculations are correct; I'm withdrawing my attempt. My guess is that if repetition of numbers is allowed, and if the order of the numbers is important (663 is distinct from 366) then there are 216 possibilities. With repetition but no particular order, I think the number is 186 possibilities.

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Combinatorial theory is based on the premise that the order of the numbers does not matter. So that 234, 243, 432 are all the same.

If no repetition is permitted, there are 6C3 = 6*5*4/(3*2*1) = 20 combinations.

If repetition is allowed,

there are a further 6*5 = 30 combinations with a pair and a singleton

and another 6 triplets.

All in all 56 combinations.

Although NOT strictly part of the answer, the number of permutations (order DOES matter), without repeat, are

6*5*4 = 120

and finally, if repeats are allowed, the number is 6*6*6 = 216 as in the previous answer.

However, remember that "combination" locks are a misnomer and in mathematics the order does not matter in combinations.

Q: How many 3 number combinations are there in the numbers 1 to 6?

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14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.

There are 15380937 of them.

300

There are: 20C3 = 1140

9

Related questions

You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.

There are 8,592,039,666 combinations of 6 numbers out of 138 numbers, like the numbers from 1 to 138.

10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.

There are 13,244 of them.

There are 15380937 of them.

Number of combinations = 45C6 = 45!/6!(45-6)! = 8,145,060

There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.

900000

There are: 20C3 = 1140

300

9

just intrested in the number combinations * * * * * Number of combinations = 56C6 = 56*55*54*53*52*51/(6*5*4*3*2*1) = 32,468,436