If it is a 4inch by 4inch (1/3foot by 1/3foot)tile and it covers a 10ft by 10ft area then it will take 900 of these tiles to cover the whole floor.
If you walk ten feet on a edge of this floor then you will have to place 30 tiles along this edge. Since the area is a square area then to find the amount of tiles just multiply 30 by 30 to get 900tiles.
This tile has an area of 1 ft2.
You will need 44 six inch tiles to cover 11 square feet.
141
1 sq foot = 144 sq inch tile area is 14 x 14 sq inch answer = 32 x 144 / (14 x 14) tiles
288 6-inch tiles are needed.
900 of them.
Are you asking how many 8 inch square tiles would cover this area The answer is 48 tiles. add on extra for wastage
13x13= 169in(one tile) 300/169= about 1.8 (amount of tiles that can fit)
440 6-inch square tiles.
One 9 inch square tile would presumably be 9in x 9in or 81in2, unless you are meaning 3in x 3in tile which is then 9in2. Regardless, the answer to your question is the total area of the floor (in square inches) divided by the total area of one tile (in square inches).
A 12 inch square tile covers a square foot. Doing the math gives an answer of 750 tiles.
The area of each tile is 16*16 sq inches = 1.77... square feet. To cover a 200 square foot square will require 200/1.77... = 112.50 = 113 tiles.