This question could have two different answers, depending on what a "6 inch tile" is. If this is a tile measuring 6x6, then its area is 36. 168 ÷ 36 = 4 and 2/3 tiles. Alternately, this could refer to a tile measuring 6 square inches (perhaps it is 2x3, or something like that). In that case, 168 ÷ 6 = 28 tiles.
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To determine how many 1.6-inch tiles you need to cover 168 square feet, first convert the tile size to square feet. A 1.6-inch tile is ( \frac{1.6}{12} ) feet, which is approximately 0.1333 feet. The area of one tile is ( 0.1333 \times 0.1333 \approx 0.0178 ) square feet. To find the number of tiles needed, divide the total area by the area of one tile: ( \frac{168}{0.0178} \approx 9444 ) tiles. Thus, you need approximately 9,444 tiles to cover 168 square feet.
252/1.5 = 168
The answer will depend on the shape of the 168 square feet. The best that you can do, leaving no room for grout, is 42 tiles. However, if the area is circular, you will require more.
448 9x6 tiles.
12 x 14 = 168 2 x 4 = 8 168 - 8 = 160 160 tiles will be needed.
168
168
1,512 16-inch squares.
14 x 12 = 168 square feet - that is 168 tiles since each is one square foot
There are 2.54 centimetres in one inch. Therefore, 168 inches is equal to 168 x 2.54 = 426.72 centimetres.
The area around the sink would take two rows of four tiles each, so that is 8 tiles which will NOT be needed. The whole floor would take twelve rows of fourteen tiles = 12 x 14 = 168. So, if we take away the 8 tiles which won't be needed we are left with 160 tiles.
1 foot = 12 inches1 foot-pound = 12 inch-pounds