142
999-1= 998
998/7 = 142.5714286 not 143, so 7 goes into 998 142 times evenly.
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999 ÷ 7 = 142 remainder 5
There can be a maximum of 2 electrons in the 7s orbital, following the Pauli exclusion principle which states that each orbital can hold a maximum of 2 electrons with opposite spins.
5.28751 7s equals 37.
8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.
999 MOD 1000 = 999
There is only one orbital in the 7s sublevel. The "7" corresponds to the principal quantum number and "s" indicates the sublevel shape, which is spherical.
Easier way than what?I presume you mean long multiplication of 999 by 999, adding 998 and adding 1.One way:999 = 1000 - 1 ⇒ 999 x 999 + 998 + 1 = (1000 - 1) x (1000 - 1) + 998 + 1= 10002 - 2 x 1000 + 1 + 998 + 1= 1000000 - 2 x 1000 + 1000= 1000000 - 1000= 999000Another way:998 + 1 = 999 ⇒ 999 x 999 + 998 + 1 = 999 x 999 + 999= 999 x (999 + 1)= 999 x 1000= 999000
If by "between" you mean "between but not including", then the answer is 9999 - 999 - 1 = 8999.If on the other hand, you mean to include both 9999 and 999, then the answer is 9999 - 999 + 1 = 9001.
999 ÷ 789 = 1 with remainder 210 OR 1.266 times.
998
There are 280 of them.
7.143, approximately. 50 ÷ 7 = 7 with remainder 1