nCr = n!/((n-r)!r!)
→ 49C8 = 49!/((49-8)!8!) = 49!/(41!8!) = 450,978,066 combinations.
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
The number of combinations is 50C6 = 50*49*48*47*46*45/(6*5*4*3*2*1) = 15,890,700
Assuming you meant how many combinations can be formed by picking 8 numbers from 56 numbers, we have:(56 * 55 * 54 * 53 * 52 * 51 * 50 * 49)/8! = (7 * 11 * 3 * 53 * 13 * 51 * 25 * 7) = 1420494075 combinations. (Also equal to 57274321104000/40320)
There are 51C6 = 51*50*49*48*47*46/(6*5*4*3*2*1) = 18,009,460 combinations.
No. There are nearly 14 million combinations of 49 things taken 6 at a time. Excel does not have that many rows or columns to support that.
there are 13,983,816 combinations.
13,983,816
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
The number of combinations is 50C6 = 50*49*48*47*46*45/(6*5*4*3*2*1) = 15,890,700
Assuming you meant how many combinations can be formed by picking 8 numbers from 56 numbers, we have:(56 * 55 * 54 * 53 * 52 * 51 * 50 * 49)/8! = (7 * 11 * 3 * 53 * 13 * 51 * 25 * 7) = 1420494075 combinations. (Also equal to 57274321104000/40320)
There are 51C6 = 51*50*49*48*47*46/(6*5*4*3*2*1) = 18,009,460 combinations.
if we do not want to use the same number more than once then the answer is: 49*48*47*46*45*44 however if we can use a number more than once the solution is: 49^6
No. There are nearly 14 million combinations of 49 things taken 6 at a time. Excel does not have that many rows or columns to support that.
7
there are many combinations of numbers that add up to 84. Some examples are 41+43, 35+49, 29+55, 24+61, and 18+66.
63
7. 72 is 49