1 degree Celsius equates to 274.15 kelvin.
Conversion: [K] = [°C] + 273.15
C =K-273.15 C=2352.2 -273.15 C=2079.05 so, 2352.2 oK=2079.05 oC
(C) + 273.15 = (K)
-146 deg C = -146 + 273.15 K = 127.15 K
fu c k you
C = K - 273.15 ⇒ 0.02 K = 0.02 - 273.15oC = -273.13oC
1 °C = 1 K and 1 ℃ = 1.8 °F
C =K-273.15 C=2352.2 -273.15 C=2079.05 so, 2352.2 oK=2079.05 oC
Chalk. C-L-I-C-K C-L-O-C-K C-L-U-C-K C-H-U-C-K C-H-I-C-K Croak Crack Crook Creek
K to C Formula: C = K - 273.15 C to K Formula: K = C + 273.15
C = K -273
#include<iostream.h> #include<conio.h> void main() { clrscr(); int i,k,a[10],c[10],n,l; cout<<"Enter the no. of elements\t"; cin>>n; cout<<"\nEnter the sorted elments for optimal merge pattern"; for(i=0;i<n;i++) { cout<<"\t"; cin>>a[i]; } i=0;k=0; c[k]=a[i]+a[i+1]; i=2; while(i<n) { k++; if((c[k-1]+a[i])<=(a[i]+a[i+1])) { c[k]=c[k-1]+a[i]; } else { c[k]=a[i]+a[i+1]; i=i+2; while(i<n) { k++; if((c[k-1]+a[i])<=(c[k-2]+a[i])) { c[k]=c[k-1]+a[i]; } else { c[k]=c[k-2]+a[i]; }i++; } }i++; } k++; c[k]=c[k-1]+c[k-2]; cout<<"\n\nThe optimal sum are as follows......\n\n"; for(k=0;k<n-1;k++) { cout<<c[k]<<"\t"; } l=0; for(k=0;k<n-1;k++) { l=l+c[k]; } cout<<"\n\n The external path length is ......"<<l; getch(); }
C to F: F = 1.8*C + 32C to K: K = C - 273.15 F to C: C = 5/9*(F- 32) F to K: K = 5/9*(F- 32) - 273.15 K to C: C = K + 273.15 K to F: K = 1.8*(K - 273.15) + 32
K to C Formula: C = K - 273.15
Formula: K = (C + 273.15)
288 plus 273 equals 561 K. (Any)degrees C +273 = degrees K
K to C Formula: C = K - 273.15 C to K Formula: K = C + 273.15
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