-146 deg C = -146 + 273.15 K = 127.15 K
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(C) + 273.15 = (K)
The answer is 127.15 K (approx.). The Kelvin scale starts at absolute zero and is used in scientific laboratories. Celsius is for general use and set 0 and 100 as melting and boiling point of water respectively. To convert from C to K, add 273.15 to C.Kelvin = Celsius + 273-146 C + 273 = 130 K.
C = K - 273.15 ⇒ 0.02 K = 0.02 - 273.15oC = -273.13oC
Add 273 to go from temperatures in degrees Celsius to Kelvin. Thus, -100 degrees Celsius is (-100+273=) 173 K.
63 deg C = 336.15 K