Set A = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }
nA = 10 (there are 10 entries in A)
|P(A)| = 2n
|P(A)| = 210 = 1024
P(A) represents the power set of A. The line brackets "|...|" represent the carnality (the count of elements). The power set is just a set of every possible set, including the empty set. I included this terminology to help research the topic further, if you are interested.
The answer is 1024.
Minor error in above answer: The term for the number of items in a set is its cardinality (not carnality).
Note that an empty set is included for the set of 11 numbers. That is 1 subset. Since order doesn't matter for this type of situation, we count the following number of subsets. 1-item subset: 11 choose 1 2-item subset: 11 choose 2 3-item subset: 11 choose 3 4-item subset: 11 choose 4 5-item subset: 11 choose 5 6-item subset: 11 choose 6 7-item subset: 11 choose 7 8-item subset: 11 choose 8 9-item subset: 11 choose 9 10-item subset: 11 choose 10 11-item subset: 11 choose 11 Note that the pattern of these values follows the Fibonacci sequence. If we add all of these values and 1 altogether, then you should get 2048 subsets that belong to the given set {1,2,3,4,5,6,7,8,9,10,11}. Instead of working out with cases, you use this form, which is 2ⁿ such that n is the number of items in the set. If there is 11 items in the set, then there are 211 possible subsets!
{1,2,4.7} is a proper subset of {1, 2, 3, 4, 4.7, 5}
{-1, 0, 1, 2, 3, 4}
There are infinitely many possible answers.For example, (1, 1, 186)or (1, 2, 93)or (10, 2, 9.3)There are infinitely many possible answers.For example, (1, 1, 186)or (1, 2, 93)or (10, 2, 9.3)There are infinitely many possible answers.For example, (1, 1, 186)or (1, 2, 93)or (10, 2, 9.3)There are infinitely many possible answers.For example, (1, 1, 186)or (1, 2, 93)or (10, 2, 9.3)
4 cups is 1 quart So 10 cups = 10/4 = 5/2 = 2 and 1/2 or 2.5 quarts
A set is a subset of a another set if all its members are contained within the second set. A set that contains all the member of another set is still a subset of that second set.A set is a proper subset of another subset if all its members are contained within the second set and there exists at least one other member of the second set that is not in the subset.Example:For the set {1, 2, 3, 4, 5}:the set {1, 2, 3, 4, 5} is a subset set of {1, 2, 3, 4, 5}the set {1, 2, 3} is a subset of {1, 2, 3, 4, 5}, but further it is a proper subset of {1, 2, 3, 4, 5}
Note that an empty set is included for the set of 11 numbers. That is 1 subset. Since order doesn't matter for this type of situation, we count the following number of subsets. 1-item subset: 11 choose 1 2-item subset: 11 choose 2 3-item subset: 11 choose 3 4-item subset: 11 choose 4 5-item subset: 11 choose 5 6-item subset: 11 choose 6 7-item subset: 11 choose 7 8-item subset: 11 choose 8 9-item subset: 11 choose 9 10-item subset: 11 choose 10 11-item subset: 11 choose 11 Note that the pattern of these values follows the Fibonacci sequence. If we add all of these values and 1 altogether, then you should get 2048 subsets that belong to the given set {1,2,3,4,5,6,7,8,9,10,11}. Instead of working out with cases, you use this form, which is 2ⁿ such that n is the number of items in the set. If there is 11 items in the set, then there are 211 possible subsets!
An improper subset is identical to the set of which it is a subset. For example: Set A: {1, 2, 3, 4, 5} Set B: {1, 2, 3, 4, 5} Set B is an improper subset of Set Aand vice versa.
An improper subset is identical to the set of which it is a subset. For example: Set A: {1, 2, 3, 4, 5} Set B: {1, 2, 3, 4, 5} Set B is an improper subset of Set Aand vice versa.
{1,2,4.7} is a proper subset of {1, 2, 3, 4, 4.7, 5}
A set "A" is said to be a subset of "B" if all elements of set "A" are also elements of set "B".Set "A" is said to be a proper subset of set "B" if: * A is a subset of B, and * A is not identical to B In other words, set "B" would have at least one element that is not an element of set "A". Examples: {1, 2} is a subset of {1, 2}. It is not a proper subset. {1, 3} is a subset of {1, 2, 3}. It is also a proper subset.
{-1, 0, 1, 2, 3, 4}
16 Recall that every set is a subset of itself, and the empty set is a subset of every set, so let {1, 2, 3, 4} be the original set. Its subsets are: {} {1} {2} {3} {4} {1, 2} {1, 3} {1, 4} {2, 3} {2, 4} {3, 4} {1, 2, 3} {1, 2, 4} {1, 3, 4} {2, 3, 4} {1, 2, 3, 4} * * * * * A simpler rationale: For any subset, each of the elements can either be in it or not. So, two choices per element. Therefore with 4 elements you have 2*2*2*2 or 24 choices and so 24 subsets.
2^5=32
1) 1/10 2) 2/10 ..... 10) 10/10 There are 10 tenths in 1, so there are 6 times that many in 6 60
The empty set is a subset.
20 1 = 1/1 = 10/10, or 10 tenths. 2 x 1 = 2 x 10/10 = 20/10 = 20 tenths